Suppose the population of a certain city is 5769 . It is expected to decrease to 4963 in 50 years. Find the percent decrease.

Answers

Answer 1
Answer:

Answer:

≈ 13.98%

Step-by-step explanation:

As the total population is 5769 in the initial period, you must find the percentage that repesents 4963 that is the expected population.

4963/5769=0.8602

Then you multiply it by 100 to transform it into percentage

0.8602*100=86.02%

Then it's just necesary to subtract that from 100% and that numbers is the percentage of decrease

100% - 86.02% = 13.98%

Also you can say that is approximately  14%


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Mrs. Curtis wants to buy online tickets for a concert. Two options are given here.Option 1: $53 for each ticket plus a shipping fee of $10

Option 2: $55 for each ticket and free shipping

What is a system of equations to represent the costs of the tickets?

Express your equations in the form of y=mx+by=mx+b where x is the number of tickets purchased and y is the total cost.

Enter your equations in the boxes.

Answers

Option 1- y= 53x+10
Option 2- y= 55x 
55x+10=53x
-53x     -53x
2x=10
x=5 

Answer:

equation 1 is y=53x + 10

equation 2 is y=55x

Step-by-step explanation:

Provide an appropriate response.39) Find a set of 7 scores that has the same mean but a smaller standard deviation than the
set {65, 71, 77, 80, 82, 90, 96}.

Answers

You don't even have to look up the definition of 'standard deviation'.  You only
have to remember that 'smaller standard deviation' means 'less spread-out'.

First, let's find the mean (average).  It's not supposed to change:

1/7th of (65 + 71 + 77 + 80 + 82 + 90 + 96) = 561/7 = 80 and 1/7 .

Now, just pick 7 scores that total 561 and are all bunched up.

The easiest way would be 80, 80, 80, 80, 80, 80, 81 .
But that's so easy that it feels like cheating.

Let's say 77, 78, 79, 80, 81, 82, and 84 .

Factor completely 2x2 − 6x − 56.(2x − 14)(x + 4)
(x − 7)(2x + 8)
2(x − 7)(x + 4)
2(x − 4)(x + 7)

Answers

The factors of the given expression are (x-7)(2x+8). Therefore, option B is the correct answer.

The given expression is 2x²-6x-56.

How do factor the quadratic expression?

Factoring an expression means rewriting it as the product of factors.

  • Write each term as the prime factorization.
  • Identify the factors that all of the terms have in common.
  • Multiply those common factors.

Now, the factorisation of the given expression is as follows:

By splitting the middle term method we can write the expression 2x²-6x-56 as 2x²-14x+8x-56.

=2x(x-7)+8(x-7)

=(x-7)(2x+8)

Therefore, option B is the correct answer.

To learn more about the factorisation visit:

brainly.com/question/13496719.

#SPJ2

2x^2 - 6x - 56
2 (x^2 - 3x - 28)

2 (x - 7)(x + 4)

What is 15% of 120 and how do you do it

Answers

15%*120=15/100*120=15/10*12 ( u can cancel 1 0 from 100 &120)=3/2*12( by cancelling by 5)=3*6( by cancelling by 2 )=18 ans,,

Prove the following theorem indirectly. We will give you a start. Prove that a triangle cannot have two right angles. A triangle cannot have two right angles. Suppose a triangle had two right angles.

Answers

A triangle that has no two right angles is called a scalene triangle.  If the triangle has two right angles, it is called isosceles triangle. A triangle with equal sides is called an equilateral triangle.

Urgent stuff, pls:))).Can someone give me polynomial with a degree of 3 or higher

Answers

A polynomial is a function that, given an input x, returns as output a sum of powers of x, each multiplied by some coefficient. Note that 1 is a power of x, since x^0=1


The degree of the polynomial is the highest exponent of x appearing in the sum.


So. if you want to build a polynomial with degree 3 or higher, you have to:


1 - Choose the degree of the polynomial to be 3 or higher, for example 5.


2 - Consider all the powers of x, with exponents up to 5: 1,x,x^2,x^3,x^4,x^5


3- Assing a coefficient to every power. We usually write a_n to indicate the coefficient of x^n. You can choose any number you like. So, for example, you can choose


a_0 = 3, a_1 = 0, a_2 = -5, a_3 = 12, a_4 = -1, a_5 = 1


4 - Multiply each power by its coefficient, and sum all the pieces:


a_0x^0 + a_1x^1 + a_2x^2 + a_3x^3 + a_4x^4 + a_5x^5


3\cdot 1 + 0\cdot x^1 + (-5)\cdot x^2 + 12\cdot x^3 + (-1)\cdot x^4 + 1\cdot x^5


3 -5x^2 + 12x^3 -x^4 + x^5