Answer:
a: 9
b: 27
Step-by-step explanation:
Let's define
P = amount of model cars that Peter has
J =amount of model cars that Jade has
A = amount of model cars that Andre has
a: We need to find out how many model cars does Peter have, i.e. we need to find out P.
We know that Andre has 36 model cars and he has 4 times as many model cars as Peter. If we write that as an equation, we have
A = 4*P = 36
Now we just have to divide by 4:
4*P/4 = 36/4
P = 9
Peter has 9 model cars.
b: Now we need to find out how many model cars does Jade have, i.e. we need to find out J.
We will resolve it as in part a:
Peter has 9 model cars and he has one-third as many model cars as Jade, that is
P = 1/3*J = 9
We multiply by 3 and we have:
1/3*J*3 = 9*3
J = 27
Jade has 27 model cars.
$124.
Jason- 20$ more than Darcy
Maria- Twice as much as Jason
Darcy- 20$ less than half of Maria's sum.
After I had written the page below, I came back up here and realized there was a much easier way.
268/2 = 134
Since the 20 Is added after, half is subtracted and you end up with
124!!
Now for my explanation done first, typed and read as I figured it out.
First and mostly, we need to find what Darcy starts with.
Let's say that Darcy has 5 dollars, to start somewhere easy. That would mean that Jason has 25 dollars since he has 20 more than her. That would mean that Maria would have 50 dollars, and the looted sum is 80.
Since that is less than a quarter of our end goal of 268$, I raised Darcy's initial amount of money to 15 to triple her money.
Math revised here- 15+20= (35*2) 70= 120
15+35+70
Since that is too low, I'm adding it to 30$.
Math revised again here- 30+20=(50*2)=100= 180
30+50+100
5 15 30
80 120 180
That is a chart determining our answers so far. There is no clear pattern, so let us continue.
Darcy starts with 50 dollars for this one.
50+20=(70*2)=140
50+70+140
260.
We are close to the sum.
Darcy starts with $52
52+20(72*2)= 144
52+72+144
268!
This means we have found how much Darcy has, and since Jason's amount depends on her, we have found both of their sums!