Using the formula P = 2L + 2W, we were able to solve for the width of a rectangle with a length of 34 ft and a perimeter of 112 ft. The width of the rectangle is 22 ft.
To find the width of the rectangle, we need to rearrange the formula P = 2L + 2W to solve for W.
Starting with P = 2L + 2W, we can isolate W by subtracting 2L from both sides:
P - 2L = 2W
Now we divide both sides by 2 to isolate W:
W = (P - 2L) / 2
Substituting the given values, we get:
W = (112 - 2(34)) / 2
W = (112 - 68) / 2
W = 44 / 2
W = 22
Therefore, the width of the rectangle is 22 ft.
In summary, using the formula P = 2L + 2W, we were able to solve for the width of a rectangle with a length of 34 ft and a perimeter of 112 ft. The width of the rectangle is 22 ft.
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A. -12(-3/4)
B. -13(3/4)
C. -12- 3/4
D. -12 + 3/4
The expression (3)(4)(-3/4) is equivalent to -9.
None of the given options is correct.
Given information:
The expression is (3) (4) (-3/4).
Multiplying 3, 4, and -3/4, we get:
(3)(4)(-3/4),
Simplify the parenthesis,
= 12(-3/4)
Multiplying,
= -36/4
Divide -36 by 4, and we get,
= -9
Therefore, the expression is equivalent to:-9
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3.2x+0.5y = 42
-1.6x-0.5y = 3.4
O (4.75, 38.8)
O (4.75, -22)
no solution
infinitely many solutions
30 milliliters every 4 hours
milliliters per hour
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