166.5 x what = 2,830.5

Answers

Answer 1
Answer: X=17 if you do 166.5 times 17 it is equal to be 2,830.5
Answer 2
Answer: 17 Because all you have to do is divide the numbers.

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a baseball diamond is shaped like a square the perimeter perimeter is 360 feet what is the length of each side

Answers

360/4=90 you need to take the 360 feet and divide it by 4 (sides) to get 9o feet per side. 
you need to divide the permimeter by 4 because a square has 4 sides
360/4=90
each side length is 90 feet

the perimeter of a square is 4 times as great as the length of any of its sides. Determine whether the perimeter of the square is proportional to the side length. Explain your reasoning

Answers

if the side of the square is a,
perimeter of a square = 4*a
therefore, whatever the side's length is, the perimeter is 4a
so, perimeter:side= 4a:a

Answer:

Step-by-step explanation:

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Are 124 and 741 relatively prime?

Answers

Yes 124 and 741 are relatively prime
Yes they very much are

Mark drew 2 triangles and 8 arrows as part of a set of 13 shapes. The only other type of shape in the set is a circle. What fraction of the set is made up of circles?

Answers

Answer: 3/13

Step-by-step explanation:

Please help
What is m HLG
____ degrees

Answers

m\angle HLG + m\angle HLI=90\n9m+25m+22=90\n34m=68\nm=2\nm\angle HLG=9\cdot2=18^(\circ)
If one quadrant equals 90 degrees then 25m+22  plus 9m equals 90 degrees solve the equation for x  first combine like terms then subtract 22 from 90. (25m+22) + (9m)= 90    34m+22=90      34m=68 Divide 68 by 34 and m=2  You can also plug 2 back into both equations and add the results. ( to equal 90).  Angle HLG is 18

Describe what happens to the graph of y=3x+4 when the slope is changed to 1/3

Answers


The graph is still a straight line, it still cuts the y-axis at the point y=4 ,
and it still slants up from left to right.

But it becomes a lot less steep.  The original line only had to go 4 inches
to the right in order to rise 1 foot.  The new line has to go 3-feet to the right
in order to rise 1 foot.