A hydraulic lift is to be used to lift a 2000-kg weight by putting a weight of 25 kg on a piston with a diameter of 10 cm. Determine the diameter of the piston on which the weight is to be placed.

Answers

Answer 1

Answer:

Answer:

88 centimeters is the diameter of the cilinder

Step-by-step explanation:

The pressure on both ends of the lift must be the same. Assuming the piston is cilindrical, its area will be A=π*r² where r is half the diameter

Since pressure P=F/A And P1=P2

F1=2000kg.g

A1=π*r²

F2=25kg.g

A2=π*0.05²

2000/(π*r²)=25/(π*0.05²)

and we solve for A1

r²=2000*0.05²/25

$r=\sqrt{(2000*0.05^2)/(25)}$

r= $√(5)$ 20*0.05/5=0.44m or 44cm

This is the radius, meaning that the diameter will be twice this number

Answer 2

Answer:

Answer:

Diameter=28,4849

Step-by-step explanation:

Remember that the formula for pistons is oftena simple rule of three, the input and output force is equal to the division of the force by the area of the application of the force:

$(25)/(78,5)= (2000)/(x)\n x=(2000*25)/(78,5) \nx=636,94cm^2$

Now that is the area of the circle, we just solve the formula of the circle to calculate the radius:

$a=\pi r^2\nr=\sqrt{(636,94)/(3,14) } \nr=14,24 cm$

Now remember that the radius is half the diameter so we just have to multiply the radius by 2:

14,24*2=28,4849

So the diameter has to be 28,4849

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X^2+ bx +c= (x + 3) (x + m)

Answers

Answer:

x= c-3m/m+3-b

Step-by-step explanation:

use Math way

Step-by-step explanation:

(b-m-3)x-3m+c =0

hope u got it!!

Difficult Math. Up to the challenge?

Answers

Answer:

We have the three angles of a triangle as an equation, so we can add them together, and they equal 180.

So:

4x+10+12x-6+3x+5= 19x+9=180

19x=171 ... so: x= 171/19 = 9.

So ABC = 102 .. Obtuse angle

BAC = 46 .. Acute angle

BCA = 32 .. Acute Angle

Edit:

Angle 1 = 180 - BAC = 180 - 46 = 134

Angle 2= 180 - ABC = 180 - 102 = 78

Which inequality is equivalent to |x-4|<9?

Answers

Answer:

–9 < x – 4 < 9

The average sales per customer at a home improvement store during the past year is $75 with a standard deviation of $12. The probability that the average sales per customer from a sample of 36 customers, taken at random from this population, exceeds $78 is:

Answers

The probability that the average sales per customer from a sample of 36 customers, taken at random from this population, exceeds $78 is 0.0668.

Calculation of the probability:

Since The average sales per customer at a home improvement store during the past year is $75 with a standard deviation of $12.

Here we need to find out the z score

= $78-75/ 12/ 36$

= 1.5

Here we considered normal distribution table, we obtain the area that corresponds to 0.25 to be 0.9332

So, the average is less or equal to 78.

Now

Subtract from 1 to get the complement.

So,

P(x>78)=1-0.9332

=0.0668

Learn more about probability here: brainly.com/question/24613748

Answer:

0.0668

Step-by-step explanation:

Assuming the distribution is normally distributed with a mean of $75,

with a standard deviation of $12.

We can find the z-score of 78 using;

$z=(x-\mu)/((\sigma)/(√(n) ) )$

$\implies z=(78-75)/((12)/(36) ) =1.5$

Using our normal distribution table, we obtain the area that corresponds to 0.25 to be 0.9332

This is the area corresponding to the probability that, the average is less or equal to 78.

Subtract from 1 to get the complement.

P(x>78)=1-0.9332=0.0668

How many numbers are between 0 and 4

Answers

Answer:

infinite rational numbers

Step-by-step explanation:

There are infinite rational numbers between 0 and 4. Now,single decimal value change like 2.34 and 2.35 can change the total value of a rational number. And there are infinite combinations of this decimal value between just two numbers.

Answer:

3 numbers

Step-by-step explanation:

A 40 N force is applied to an object with a mass of 0.1 kg on a frictionless surface. What is the acceleration of the object?

Answers

The acceleration of the object is 400 m/s²

What is the acceleration of the object?

To find the acceleration of an object when a 40 N force is applied to it with a mass of 0.1 kg on a frictionless surface, we can use Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.

The formula for Newton's second law of motion is:

F = ma

where:

F is the net force,

m is the mass of the object,

a is the acceleration.

In this case, the net force is 40 N and the mass of the object is 0.1 kg.

Substituting these values into the formula, we get:

40 N = (0.1 kg) a

Solving for a, we get:

a = 400 m/s²

Therefore, the acceleration of the object is 400 m/s²