Metallic silver has a density of 10.50. what is the mass, in g, of a silver ingot that is 28.0 cm long, 4.90 cm wide, and 3.60 cm thick?

Answers

Answer 1

Answer:

Final answer:

The mass of the silver ingot is found by multiplying its volume with the density of metallic silver. The volume is calculated using the ingot's dimensions, and the final mass is approximately 5186.16 grams.

Explanation:

To determine the mass of a silver ingot based on its dimensions and density, we can use the formula mass = density × volume. First, we calculate the volume of the ingot by multiplying its length (28.0 cm), width (4.90 cm), and thickness (3.60 cm):
Volume = length × width × thickness
= 28.0 cm × 4.90 cm × 3.60 cm
= 493.92 cm³
Next, we use the density of metallic silver, 10.50 g/cm³, to find the mass:
Mass = density × volume
= 10.50 g/cm³ × 493.92 cm³
= 5186.16 g
The mass of the silver ingot is therefore approximately 5186.16 grams.

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Answer 2

Answer:

Answer:

5190 g

Step-by-step explanation:

Calculate the volume:

28.0 cm × 4.90 cm × 3.60 cm = 493.92 cm³

Density is mass divided by volume:

D = M / V

Solving for mass:

M = D V

Substituting values:

M = (10.50 g/cm³) (493.92 cm³)

M = 5186.16 g

Rounding to three significant figures, the mass is 5190 g.

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Answers

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Answers

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Answers

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