The unstable arrangement of atoms that forms momentarily at the peak of the activation-energy barrier is known as the what?

Answers

Answer 1

Answer: The unstable arrangement of atoms that forms at the peak of the activation energy is called the transition state. If I remember correctly It is the point in which all the atoms or molecules (involved in the reaction) collide in the correct orientation to brake the bonds of the reactants and form the bonds in the products.

I hope this helps. Let me know if anything is unclear.

Answer 2

Answer:

Answer:

activated complex.

Explanation:

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Stoichiometry! Please note:
- Use 6.022x1023 for avogadro’s number
- Ignore sig figs and do not round the final answer.
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Answers

Answer:

a) 13.2 moles $2H_(2)O$

b) 79.33 grams of $2H_(2)O$

Explanation:

First, we'll need to balance the equation

$H_(2(g)) + O_(2(g))$ → $H_(2)O_((g))$

There are 2 (O) on the left and only one on the right, so we'll add a 2 coefficient to the right.

$H_(2(g)) + O_(2(g))$ → $2H_(2)O_((g))$

Now there are 4 (H) on the right and only 2 on the left, so we'll add a 2 coefficient to the ( $H_(2)$ ) on the left.

$2H_(2(g)) + O_(2(g))$ → $2H_(2)O_((g))$

The equation is now balanced.

a) This can be solved with a simple mole ratio.

4.6 moles $O_(2)$ × $(2 moles H_(2)O)/(1 mole O_(2))$ = 13.2 moles $2H_(2)O$

b) This problem is solved the same way!

2.2 moles $H_(2)$ × $(2 moles H_(2)O)/(2 moles H_(2))$ = 2.2 moles $2H_(2)O$

However, this problem wants the mass of $2H_(2)O$ , not the moles.

The molecular weight of $2H_(2)O$ is the weight of 4 (H) molecules and 2 (O) molecules (found on the periodic table). So,

4(1.008) + 2(15.999) = 36.03 g/mol

2.2 moles $2H_(2)O$ × $(36.03 g)/(1 mol)$ = 79.33 grams of $2H_(2)O$

The longer the bond, the smaller the bond enthalpy. the longer the bond, the smaller the bond enthalpy. false true

Answers

True

As the shorter the bond, the stronger it is hence more energy will be required to overcome this bond

Final answer:

The statement 'The longer the bond, the smaller the bond enthalpy' is true as bond length and bond enthalpy have an inverse relationship. As bond strength increases (with an increase in electron pairs in the bond), bond length decreases. So longer bonds, indicating weaker bonding, have smaller bond enthalpies.

Explanation:

The statement 'The longer the bond, the smaller the bond enthalpy' is true. The bond length and bond enthalpy have an inverse relationship. As the strength of a bond increases with the increase in the number of electron pairs, the bond length decreases. Thus, triple bonds are generally stronger and shorter than double bonds between the same two atoms, and by the same logic, double bonds are stronger and shorter than single bonds.

For example, if we consider the bonds between carbon and various atoms in a group, we find the bond strength typically decreases as we move down the group - C-F has a bond enthalpy of 439 kJ/mol, C-Cl has 330 kJ/mol, and C-Br is at 275 kJ/mol.

The bond energy, essentially the enthalpy required to break the bond, is a representation of its strength. Thus, a longer bond, indicating weaker bonding, will have a smaller bond enthalpy.

Learn more about Bond Enthalpy here:

brainly.com/question/29633366

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The interaction of tectonic plate boundaries is associated with which of the following events? Hurricanes Tropical storms Earthquakes Tornados Previous Question

Answers

Answer:

terremotos

Explanation:

How can an iceberg (temperature=0 Celsius) have more energy than a burning match head (temperature=230 Celsius)?

Answers

A burning match head whose temperature is 230 degree Celsius have more energy than an iceberg whose temperature is 0 degree Celsius.

What is Kinetic energy ?

Kinetic energy is a form of energy in which an object possesses due to its motion. The kinetic energy of an object is depends up on both the velocity and mass. The S.I unit of Kinetic energy is Joules.

The temperature of burning match head is given 230 degree Celsius and temperature of iceberg is given 0 degree Celsius. A burning match head has a higher temperature than the iceberg due to average molecule in the burning match head moves faster than the average molecule in the iceberg.

Thus, from above conclusion we can say that A burning match head whose temperature is 230 degree Celsius have more energy than an iceberg whose temperature is 0 degree Celsius.

Learn more about the Kinetic Energy here: brainly.com/question/114210

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temperature is the average energy of each particle and does not really give you an indication of the total internal energy. That being said, total internal energy is the sum of all of the molecule's energy in a given object so it would make sense that an ice berg (having a huge number molecules at a lower average energy) would have more internal energy than a match head (having a much smaller number of molecules at a higher average energy). Basically, the fact that ice bergs tend to be huge and contain much more molecules than a match head, means that ice bergs can have a larger total internal energy which means they store more energy.

I hope this helps.

In performing chest compressions on a child, the breastbone is compressed to the depth of how many inches? a) 1/2 b) 1 1/2 c) 2. d) 2½

Answers

Answer: A is correct

Explanation: sorry if its wrong

4. How many protons are there in this atom?5. How many neutrons are there in this atom?
6. How many electrons are there in this atom?
7. What is the atomic weight of this atom?
8. Does the mass on the periodic table round to
the mass this atom has?
9. What atom is this?
9p+
10 n°
10. For each electron shown, write on the diagram to indicate which orbital (1s, 2s, 2p,...)
each electron is in.
11. Draw the orbital filling diagram for this atom. (Orbital filling is the thing with the boxes
and the arrows).
12. Write the electron configuration (1s"2s*) for this atom.