PHYSICS MIDDLE SCHOOL

Rocks are composed of different kinds ofA) soils.
B) sands.
C) minerals.
D) water crystals.

Answers

Answer 1
Answer: Answer: C) Minerals
Answer 2
Answer:

rocks are made up from the makeup of minerals

so my answer is C.)minerals

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a bus travelling on a straight road at 25m/s accelerates uniformly at 5m/s squared for 2 seconds. find its speed in kilometres per hour

Answers

Answer:

126 kmh⁻¹

Explanation:

We can simply solve this by applying motion equations

where  

v - final velocity

u - initial velocity

a-acceleration

t - time

v = u + at

  = 25 + 5×2 = 35 ms⁻¹

  = (35/1000)×3600 = 126 kmh⁻¹

What is the period of vibration for a wave with a frequency of 100 hertz?

Answers

The number of back-and-forth vibrations in a unit of time is an object's frequency. A complete back-and-forth vibration is one cycle. 1 Hz is one vibration or wave cycle per second!

Answer:

100 seconds

Hope this Helps :)

A merry -go-round rotates at the rate of 0.4rev / s with an 78 kg man standing at a point 1.5 m from the axis of rotation. What is the new angular speed when the man walks to a point m from the center? Consider the merry-go-round is a solid 11 kg cylinder of radius of 1,5 m. Answer in units of rad/s. 024 (part 2 of 2) 10.0 points What is the change in kinetic energy due to this movement ? Answer in units of

Answers

1) Final angular velocity is 5.22 rad/s

2) Change in kinetic energy: 639.8 J

Explanation:

1)

In absence of external forces, the angular momentum of the merry-go-round must be conserved.

So we can write:

L_1 = L_2\nI_1\omega_1 = I_2 \omega_2

where

I_1 is the initial moment of inertia

I_2 is the final moment of inertia

\omega_1 is the initial angular velocity

\omega_2 is the final angular velocity

At the beginning, we have:

\omega_1=0.4 rev/s \cdot 2\pi = 2.51 rad/s

The moment of inertia is the sum of the moment of inertia of the cylinder + the moment of inertia of the man, therefore:

I_1 = (1)/(2)MR^2+mr^2=(1)/(2)(11)(1.5)^2+(78)(1.5)^2=187.9 kgm^2

The man later walks to a point 1 m from the centre, so the final moment of inertia is:

I_2 = (1)/(2)MR^2+mr^2=(1)/(2)(11)(1.5)^2+(78)(1)^2=90.4 kgm^2

Therefore, the final angular velocity is

\omega_2 = (I_1 \omega_1)/(I_2)=((187.9)(2.51))/(90.4)=5.22 rad/s

2)

The angular velocity of the merry-go-round rotating is given by

K=(1)/(2)I\omega^2

In the  first situation, we have

I_1 = 187.9 kg m^2\n\omega=2.51 rad/s

Therefore

K_1 = (1)/(2)(187.9)(2.51)^2=591.8 J

In the second situation, we have

I_2= 90.4 kg m^2\n\omega_2=5.22 rad/s

Therefore

K_2=(1)/(2)(90.4)(5.22)^2=1231.6 J

So the change in kinetic energy is

\Delta K = K_2 - K_1 = 1231.6-591.8=639.8 J

Learn more about circular motion:

brainly.com/question/2562955

brainly.com/question/6372960

#LearnwithBrainly

What type of reaction occurs when you strike a match?

Answers

The type of reaction is combustion 

I'm probably wrong, but friction?

In a game of pool why will the balls eventually stop after a collision

Answers

Everything we see happening on Earth has friction along with it. 
For a pool ball, it's the work the ball does bending all the little cloth
fibers out of the way as it rolls along the table, and also the work it
does pushing air out of the way.  These things rob a little bit of each
ball's kinetic energy, so that it eventually stops rolling.

Note:  Gravity is not the answer.

Suppose you are standing on a skateboard and shoot a paintball gun at your friend. Which direction relative toyour friend will you move? Explain. _

Answers

Answer:

I will move way from my friend.

Explanation:

As I shoot the paintball towards my friend, the gun exerts a force on it that sends it moving towards my friend, and according to newtons third law, the paintball exerts an equal and opposite force on me, which causes me to move in the opposite direction of the movement of the paintball; this direction is away from my friend.

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