Simple chem question - please help!Given the equation: N2 +2O2 → 2NO2, what mass of oxygen is required to react completely with 7g of nitrogen?

A) 8 g
B) 16 g
C) 32 g
D) 64 g

Answers

Answer 1
Answer: Molar mass O₂ = 32.0 g/mol and N₂ = 28.0 g/mol

 N₂ +2 O₂ → 2 NO₂

28.0 g -------> 32.0 * 2
7 g ----------> ?

Mass of O₂ = 7 * 32.0 * 2 / 28.0

Mass of O₂ = 448 / 28.0

= 16 g of O₂

Answer B

hope this helps!
Answer 2
Answer:

Answer:

guy above is right

Explanation:


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How many moles of O2 would be consumed if 13.673 g of V were consumed according to the reaction below?

Answers

To determine how many moles of O2 would be consumed if 13.673 grams of V (vanadium) were consumed in a chemical reaction, you'll first need to know the balanced chemical equation for the reaction. I'll assume the reaction is as follows:

V + O2 → VO2

From the balanced equation, you can see that 1 mole of V reacts with 1 mole of O2 to form 1 mole of VO2. This means that the mole ratio of V to O2 is 1:1.

Now, calculate the number of moles of V in 13.673 grams:

Moles of V = Mass (grams) / Molar mass (g/mol)

The molar mass of V is the atomic mass of vanadium, which is approximately 50.94 g/mol.

Moles of V = 13.673 g / 50.94 g/mol ≈ 0.2684 moles

Since the mole ratio of V to O2 is 1:1, the number of moles of O2 consumed will also be approximately 0.2684 moles.

So, 0.2684 moles of O2 would be consumed if 13.673 grams of V were consumed in the reaction.

The process that ice on mount Everest goes through when heated from 10 degree f to 305 kelvin.

Answers

water melts at 32 F and boils at 212 F
if we change these values into Kelvin then
melting point of water is 273.15 K and boiling point is 373.15 kelvin..
  for melting it is necessary for ice to get warm so it attains heat 10 F to 32 F...
then ice melts but during this temperature remains constant..
the energy required for melting is 333    kJ/Kg K
then water is warmed at 305 Kelvin....    :)

A compound that contains both potassium and oxygen formed when potassium metal was burned in oxygen gas. the mass of the compound was 7.11 grams. The mass of the potassium metal was 3.91 grams. What mass of oxygen was involved in this reaction? Justify your answer.

Answers

Answer:
             3.2 g of O₂

Solution:
             This reaction is for the formation of Potassium Superoxide, The reaction is as follow,

                                           K  +  O₂     →     KO₂

First let us confirm that either the given amount of Potassium produces the given amount of Potassium oxide or not,
So,
As,
                39.098 g (1 mole) K produced  =  71.098 g of K₂O
So,
                          3.91 g of K will produce  =  X g of K₂O

Solving for X,
                      X  =  (3.91 g × 71.098 g) ÷ 39.098

                      X  =  7.11 g of K₂O

Hence, it is confirmed that we have selected the right equation,
So,
As,
                     39.098 g of K required  =  32 g of O₂
So,
                     3.91 g of K will require  =  X g of O₂

Solving for X,
                     X  =  (3.91 g × 32 g) ÷ 39.098 g

                     X  =  3.2 g of O₂
The mass of oxygen  that was involved  in the reaction is calculated as below

 mass of the oxygen =mass of the  compound- mass  of the  potassium

that is  7.11 grams -3.91 grams= 3.2  grams  of oxygen  is involved

This is because the mass of the compound composes the mass of potassium + mass of the oxygen

A bond exists between A and B in the compound AB. A and B are sharing electrons. The type of bond is ____

Answers

Answer: Covalent

Explanation:

A covalent bond is formed when an element shares its valence electron with another element. This bond is formed between two non metals.  Example: H_2

An ionic bond is formed when an element completely transfers its valence electron to another element. The element which donates the electron is known as electropositive element and the element which accepts the electrons is known as electronegative element. This bond is formed between a metal and an non-metal. Example: NaCl

Thus bond formed by sharing of electrons is covalent bond.

They are covalent bonds.
Covalend bonds share
Ionic bonds transfer

A bus traveled 280 kilometers between two cities . It left the first city at 3:00 p.m. and arrived at the second city at 7:00 p.m. What was the average speed of the bus during the trip ?

Answers

Answer:

70 kilometers per hour

Explanation:

280 kilometers ÷ 4 hours (7:00 pm - 3:00 pm = 4 hours) = 70 kilometers per hour

Hope this helps! Sorry if wrong. You are loved and you are beautiful/handsome!

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The complete combustion of ethanol, C₂H₅OH (FW = 46.0 g/mol), proceeds as follows: C_2H_5OH(l) + 3O_2(g) \rightarrow 2CO_2(g) + 3H_2O(l); ΔH = −555 kJ What is the enthalpy change for combustion of 15.0 g of ethanol?

Answers

Answer: 181 kJ

Explanation:

The balanced chemical reaction is;

C_2H_5OH(l)+3O_2(g)\rightarrow 2CO_2(g)+3H_2Ol)\Delta H=-555jJ

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=(15.0g)/(46.0g/mol)=0.326moles

According to stoichiometry:

1 mole of C_2H_5OH on complete combustion give= 555 kJ

Thus 0.326 moles of C_2H_5OH on complete combustion give=(555)/(1)* 0.326=181kJ

Thus the enthalpy change for combustion of 15.0 g of ethanol is 181 kJ