Answer:
Company revealed that, One half of employees will get bonus, if the production of cookies increased by 15 %.
And , other half of employees will not get the bonus.
And,
The group who didn't get the bonus, their production increased by mean of 20.
And, the production in the bonus group increased by mean of 10 only.
To check whether results are significant or not,we will follow the following steps
1. C. Randomly separate the employees' individual results into two groups.
2. D.Calculate the mean of each group.
3. B. Calculate the difference of the means
4. E. Run the experiment many times.
5. A .Calculate the probability of a difference of 10
A.
{3}
B.
{3, –3}
C.
{9, –9}
D.
{9}
Answer:
0.9533
Step-by-step explanation:
(a) Probability that a randomly selected woman's height is less than 65 inches:
Using the z-score formula:
�
=
�
−
�
�
Z=
σ
X−μ
Where:
�
X = 65 inches
�
μ = 64.3 inches
�
σ = 2.7 inches
�
=
65
−
64.3
2.7
≈
0.2593
Z=
2.7
65−64.3
≈0.2593
Now, find the probability associated with this z-score, which is approximately 0.6010 (rounded to four decimal places).
(b) Probability that the mean height of 43 randomly selected women is less than 65 inches:
Using the Central Limit Theorem:
�
μ (mean of the sample means) remains 64.3 inches.
�
sample mean
σ
sample mean
(standard deviation of the sample means) is calculated as
2.7
43
≈
0.4115
43
2.7
≈0.4115.
Now, find the z-score for a sample mean of 65 inches:
�
=
65
−
64.3
0.4115
≈
1.6924
Z=
0.4115
65−64.3
≈1.6924
The probability associated with this z-score is approximately 0.9533 (rounded to four decimal places).
Answer:
4,8,12,16,20,24,28,32,36,40,44,48,52,56,60,64,68,72,76,80,84,88,
Step-by-step explanation: