Explain the law of motion needed to solve this problem and then solve it. On Planet Zorg, a 30 kg barbell can be lifted by only exerting a force of 180 N. What is the acceleration of gravity on Planet Zorg? Predict how the motion of this object would change if on Earth. Please help. I have no idea how to do this.

Answers

Answer 1

Answer: Law of Motion says that every object that moves uniformly tends to stay in that state unless a force is applied to it. Force is equal to the mass of that object multiplied by its acceleration:
F = m × a
The unit of force is N = kg * m/s².

Q1: The acceleration of gravity on Planet Zorg is unknown:
a = ?

We know:
F = 180 N
m = 30 kg

Since F = m × a, then:
a = F/m
a = 180 N/30kg
a = 180 kg*m/s² / 30 kg
a = 6 m/s².
So, the acceleration of gravity on Planet Zorg is 6 m/s².

Q2: Force needed to change the motion of the object on the Earth is unknown:
F = ?

We know:
a = 9.8 m/s²
m = 30 kg

If F = m × a, then:
F = 30 kg × 9.8 m/s²
F = 294 N
So, force needed to change the motion of the object on the Earth is 294 N.

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carnivores,herbivore,omnivore,and decomposers

Which of the following could result in secondary succession?a. the formation of a tall sand dune on a previously grassy beach
b. a vast glacier in motion forming a U-shaped valley on its wake
c. a volcanic eruption that covers most of what used to be a forest
d. an introduced species that devastates native plants as it feeds

Answers

Actually the correct answer is D.

D. An introduced species that devastates native plants as it feeds

is the correct answer.

Hope I helped!

Why would scientists want to monitor the migration habits of red-winged blackbirds in MA?

Answers

Answer:

Blackbird and Oriole : Varieties of swamps, shrubs, swamps, and dry grasses; foraging in arable land and water. The species is most commonly found in freshwater marshes, but in wooded or bushy marshes, weed fields, hay fields, and salt marshes also have levels on the upper edge. Usually foraging in other open habitats, such as fields and tidal flats; outside the breeding season, flocks of chickens gather in farmlands, pastures and feedlots.

Among the birds we are most familiar with, the red wings seem to sing nasal sounds on every swamp and wetland from coast to coast. They are particularly bold, and a few often attack larger birds, such as eagles or crows, and they fly over their nesting areas. When singing, the male's red shoulder patches are hidden under the body feathers most of the time, which is very beautiful. Outside the nesting season, red wings sometimes live in large areas.

That's why. Hope it helps.

Final answer:

Scientists monitor the migration habits of red-winged blackbirds in MA for reasons related to conservation, ecosystem dynamics, and tracking the effects of climate change.

Explanation:

Scientists would want to monitor the migration habits of red-winged blackbirds in Massachusetts for several reasons:

Conservation: Monitoring migration habits helps scientists understand the patterns and behaviors of red-winged blackbirds, which can contribute to their conservation efforts.
Ecosystem dynamics: Red-winged blackbirds play important roles in the ecosystem, and studying their migration habits can provide insight into the health of ecosystems and the impacts of environmental changes.
Climate change: Studying the migration habits of red-winged blackbirds can help scientists track the effects of climate change, such as shifts in timing and routes of migration.

Learn more about migration habits of red-winged blackbirds here:

brainly.com/question/18850306

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Why is the stigma of a flower sticky

Answers

The Stigma can be hairy or sticky to trap pollen.

The stigma of a flower is sticky to trap pollen

Which of the following statements regarding a DNA double helix is true? The amount of adenine is equal to the amount of thymine, and the amount of guanine is equal to the amount of cytosine. The amount of adenine is equal to the amount of uracil, and the amount of guanine is equal to the amount of cytosine. The amount of adenine is equal to the amount of guanine, and the amount of thymine is equal to the amount of cytosine. The amount of adenine is equal to the amount of guanine, and the amount of uracil is equal to the amount of thymine. The amount of adenine is equal to the amount of cytosine, and the amount of guanine is equal to the amount of thymine.

Answers

Answer:

Option (1).

Explanation:

DNA (deoxyribo nucleic acid ) is the genetic material present in all the organisms except some viruses. DNA structure follows the Chargaff's rule.

Accoprding to Chargaff's rule, the ratio of purines to pyrimidines in a DNA molecule is equal to 1. The amount of guanine is nearly equal to the amount of cytosine whereas the amount of thymine is nearly equal to the amount of adenine.

Thus, the correct answer is option (1).

A plant with the dominant trait, wrinkled seeds, is crossed with a plant that has non-wrinkled seeds. All of the offspring are all wrinkled-seeded. What is the likelihood that the gametes of the wrinkled-seeded parent plant contain one non-wrinkled allele?

Answers

The answer is 0 percent.

If we represent dominant trait (wrinkled seeds) with A and recessive trait (non-wrinkled seeds) with a, then genotypes are AA (dominant homozygous), Aa (heterozygous), and aa (recessive homozygous). The phenotype of wrinkled seed is determined by genotypes either Aa or AA. Since the cross of a plant with wrinkled seed with a plant with non-wrinkled sees gives only wrinkled-seeded offspring, the plant with wrinkled seeds must be dominant heterozygous.
Let's look at both examples.
If wrinked-seeded parent contains one non-wrinkled allele, it must be heterozygous (Aa):

Parents: Aa x aa
Offspring: Aa Aa aa aa

So, the 50% of offspring has wrinkled seeds and 50% has non-wrinkled seeds.

If the wrinkled-seeded parent does not contain any non-wrinkled allele:
Parents: AA x aa
Offspring: Aa Aa Aa Aa

Thus, all of the offspring are heterozygous and all of them have wrinkled seeds.

Answer:

a)0%

Explanation:

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