−2x+15y=−24
2x+9y=24
Add the two equations together.
-2x +2x = 0
15y + 9y = 24y
-24+24 = 0
The two equations when added become:
24y = 0
Solve for y:
divide both sides by 24:
y = 0/24 = 0
The value of Y is 0
Now replace Y in one of the equations and solve for x:
2x+9(0) = 24
2x + 0 = 24
2x = 24
Divide both sides by 2:
x = 24/2
x = 12.
The value of x is 12
The solution is (12,0)
Answer:
The solution is ( x , y ) = ( 12 , 0 )
Step-by-step explanation:
[ Refer to the attachment ]
Answer: 8/10
Step-by-step explanation: Using the place value chart, we can see that 0.8 means eight-tenths which can be written as the fraction 8/10. Since 8/10 is not in lowest terms, we need to divide both the numerator and denominator by the greatest common factor of 8 and 10 which is 2 to get 4/5.
Therefore, 0.8 can be written as the fraction 8/10.
The decimal number 0.8 in the simplest fraction form will be 4/5.
A fraction number is a number that represents the part of the whole, where the whole can be any number. It is in the form of a numerator and a denominator.
The decimal number is given below:
⇒ 0.8
Multiply and divide the expression by 10. Then we have
⇒ 0.8 x 10 / 10
⇒ 8 / 10
⇒ 4 / 5
More about the fraction number link is given below.
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Answer:
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3/4
11/16
9/16
1/4
3/16
Answer:
Therefore, the correct answer is 9/16.
Step-by-step explanation:
To determine the probability that mn is an even integer, we need to consider the possible values of m and n.
Set P contains the elements (2, 3, 5, 5, 6), and set Q contains the elements (1, 2, 3, 4).
For mn to be an even integer, either m or n must be an even number.
In set P, there are two even numbers (2 and 6) out of a total of five elements. So, the probability of selecting an even number from set P is 2/5.
In set Q, there are two even numbers (2 and 4) out of a total of four elements. So, the probability of selecting an even number from set Q is 2/4 or 1/2.
To find the probability that mn is an even integer, we can consider the two cases:
If m is even and n is any number:
The probability of m being even from set P is 2/5, and the probability of n being any number from set Q is 1 (since any number can be selected from set Q). Therefore, the probability of mn being even in this case is (2/5) * 1 = 2/5.
If m is any number and n is even:
The probability of m being any number from set P is 1 (since any number can be selected from set P), and the probability of n being even from set Q is 1/2. Therefore, the probability of mn being even in this case is 1 * (1/2) = 1/2.
We can add these two probabilities to find the overall probability that mn is an even integer:
Probability = (2/5) + (1/2) = 4/10 + 5/10 = 9/10.
Therefore, the correct answer is 9/16.
B. csc right triangle C right triangle equals fraction 3 over 2
C. csc right triangle B right triangle equals fraction 6 over 5
D. csc right triangle C right triangle equals fraction 5 over 6
Can you send a picture of the triangle. Maybe take a screen shot?