CAN SOMEONE PLEASE HELP ME WITH THIS PROBLEM
Answers
Answer:
V ≈ 2011 cm³
Step-by-step explanation:
The volume (V) of a cylinder is calculated as
V = area of base × perpendicular height
V = πr²h ( r is the radius and h the height )
Here r = 8 and h = 10, thus
V = π × 8² × 10
= π × 64 × 10 = 640π ≈ 2011 cm³ ( to nearest whole number )
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gloria earned $26 for babysitting 4 hours. write and solve an equation in the form of y= kx, where y refers to dollars and x refers to hours worked, to determine how much gloria would earn after babysitting 25 hours.
Answers
Answer:
$160
Step-by-step explanation:
80 * $2
$160
Answer: $160
1. 63d = t + 3
2. d = 21t
3. 3t = 63d
4. 3d = t + 63
Answers
Answer:
please mark as brainliest ( 3. 3t=63d)
Step-by-step explanation:
3t=63d
Answers
8, 16, 24, 32, 40, 48, 56, 72, 80, 88, 96 are all divisible by 8.
We also know that his current age is the square of his son's age. So we can check the numbers that follow the multiples of eight to see if they'll work.
The subsequent numbers, in order, are
9, 17, 25, 33, 41, 49, 57, 73, 81, 89, 97
Now, let's list which ones are squares, meaning a number multiplied by itself is equal to anther number.
9 is the square of 3
25 is the square of 5
49 is the square of 7
81 is the square of 9
Only these four will work, but right now, ANY of these four will work. Let's use a little science to narrow it down.
It is scientifically improbable for a 9-year-old to have a 3-year-old son, so we'll rule that one out. It's also highly unlikely that an 81-year-old has a 9-year-old son, so we'll cross that off the list, as well.
This leaves a 25-year-old man with a 5-year-old son, and a 49-year-old man with a 7-year-old son, both of which are most likely.
At this point, you can choose whichever you'd like, or put down both as the answer.
The man and his son's present ages are either 25 and 5, or 49 and 7.
Answers
Answer:
Step-by-step explanation:
1) (xy+ 9y + 2) and (xy – 3)
Each term of second expression will be multiplied by first bracket.
xy(xy+9y+2) -3(xy+9y+2)
x²y²+9xy²+2xy-3xy-27y-6
x²y²+9xy²-xy-27y-6
2)(2xy + x + y) and (3xy2 – y)
3xy²(2xy+x+y) -y(2xy+x+y)
6x²y³+3x²y²+3xy³-2xy²-xy-y²
6x²y³ – 2xy² + 3x²y² – xy + 3xy³ – y²
3) (x – y) and (x + 3y)
x(x-y) +3y(x-y)
x²-xy+3xy-3y²
x²+2xy-3y²
4) (xy + 3x + 2) and (xy – 9)
xy(xy + 3x + 2) -9(xy + 3x + 2)
x²y²+3x²y+2xy-9xy-27x-18
x²y²+3x²y-7xy-27x-18
5) (x2 + 3xy – 2) and (xy + 3)
xy(x2 + 3xy – 2) +3(x2 + 3xy – 2)
x³y+3x²y²-2xy+3x²+9xy-6
x³y+3x²+3x²y²+7xy-6
6) (x + 3y) and (x – 3y)
x(x + 3y) -3y(x + 3y)
x²+3xy-3xy-9y²
x²-9y² ....
Answer: (xy + 9y + 2) and (xy – 3) —> x3y + 3x2 + 3x2y2 + 7xy – 6
(2xy + x + y) and (3xy2 – y) —> 6x2y3 – 2xy2 + 3x2y2 – xy + 3xy3 – y2
(x – y) and (x + 3y) —> (x + 3y) and (x – 3y)
(xy + 3x + 2) and (xy – 9) —> x2y2 + 3x2y – 7xy – 27x – 18
Step-by-step explanation:
I think that’s right I’m sorry if it’s not.
Answers
Step-by-step explanation:
Consider the provided information.
Sandy charges each family that she babysits a flat fee of $10 for the night and an extra $5 per child.
Let x is the number of child, Sandy charges fixed fee of $10 and $5 for each child. Thus, the charges for one night is:
Kimmi charges $25 per night no matter how many children a family has. Thus, the charges for one night is:
Now we need to write an equation that would compare the two girls charges:
Thus, the required equation is.
Now we need to find how many children a family have in order to be the same charges.
For the same charges solve the equation as shown:
So, the number of children has to be 3 for same charge.
sandy= $10+$5c
kimmi= $25n
if sandy babysits 3 children for one night they will both be the same price
sandy= $10+5(3)=$25
kimmi= $25
2^(x+3) = 512
Answers
ln(2^(x + 3)) = ln(512)
(x + 3)ln(2) = ln(512)
ln(2) ln(2)
(x + 3)ln(2) = ln(2^9)
ln(2) ln(2)
(x + 3)ln(2) = 9ln(2)
ln(2) ln(2)
x + 3 = 9
- 3 - 3
x = 6