What is the mass of silver chlorate (191.32 g/mol) that decomposes to release 0.466L of oxygen gas at STP? AgC1036) _AgCl). _026) A) 1.33g B) 597 E) 7.968 C) 3.988 D) 2658

Answers

Answer 1
Answer:

Answer : The mass of silver chlorate will be 2.654 grams.

Explanation :

The balanced chemical reaction is,

2AgClO_3\rightarrow 2AgCl+3O_2

First we have to calculate the moles of oxygen gas at STP.

As, 22.4 L volume of oxygen gas present in 1 mole of oxygen gas

So, 0.466 L volume of oxygen gas present in (0.466)/(22.4)=0.0208 mole of oxygen gas

Now we have to calculate the moles of silver chlorate.

From the balanced chemical reaction, we conclude that

As, 3 moles of oxygen produced from 2 moles of silver chlorate

So, 0.0208 moles of oxygen produced from (2)/(3)* 0.0208=0.01387 moles of silver chlorate

Now we have to calculate the mass of silver chlorate.

\text{Mass of }AgClO_3=\text{Moles of }AgClO_3* \text{Molar mass of }AgClO_3

Molar mass of silver chlorate = 191.32 g/mole

\text{Mass of }AgClO_3=0.01387mole* 191.32g/mole=2.654g

Therefore, the mass of silver chlorate will be 2.654 grams.


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Grunge is a rock style from Detroit. True False

Answers

Answer:

FALSE

Explanation:

Grunge refers to the genre of rock music and the fashion inspired by it. It originated in the mid-1980s in Seattle, Washington State.

Grunge was described as the fusion of punk rock and heavy metal.

This genre of music became popular in the early mid-1990s and included lyrics based on the theme of emotional and social alienation, betrayal, abuse, trauma etc.    

Which substance yields hydroxide ion as the only negative ion in aqueous solution?

Answers

Missing question:
a. Mg(OH)2.
b. CH3Cl.
c. MgCl2 .
d. C2H4(OH)2.
Answer is: a. Mg(OH)₂.
An Arrhenius base is a substance that dissociates in water to form hydroxide ions (OH⁻).
In this example magnesium hydroxide is an Arrhenius base:
Mg(OH)₂(aq) → Ba²⁺(aq) + 2OH⁻(aq).
CH₃Cl and C₂H₄(OH)₂ are organic compound and will not give hydroxide ions in water, MgCl₂ is neutral salt and it will give Cl⁻ ions.


A rigid container of gas has a pressure of 1.72 atm and temperature of 21 oC. If the temperature increases to 85 oC, what is the new pressure in atm?

Answers

Answer:

the new pressure is 2.09 atm

Explanation:

you have to use gay lussac's law so the formula is

p1/t1 = p2/t2

and convert C to Kelvin k=C+273.15

1.72atm/294.15 = p2/358.15

solve for p2 by multiplying 358.15 on both sides

p2=2.09 atm

What is the pH at each of the points in the titration of 25.00 mL of 0.2000 MHCl by 0.2000 M NaOH:
i) Before adding NaOH

ii) After adding 24.00 mL NaOH

Answers

Answer:

i) pH = 0.6990

ii) pH = 2.389

Explanation:

i) Before adding aqueous NaOH, there are 25.00 mL of 0.2000 M HCl. HCl reacts with the water in the aqueous solution as follows:

HCl + H₂O ⇒ H₃O⁺ + Cl⁻

The HCl and H₃O⁺ are related to each other through a 1:1 molar ratio, so the concentration of H₃O⁺ is equal to the HCl concentration.

The pH is related to the hydronium ion concentration as follows:

pH = -log([H₃O⁺]) = -log(0.2000) = 0.699

ii) Addition of NaOH causes the following reaction:

H₃O⁺ + NaOH ⇒ 2H₂O + Na⁺

The H₃O⁺ and NaOH react in a 1:1 molar ratio. The amount of NaOH added is calculated:

n = CV = (0.2000 mol/L)(24.00 mL) = 4.800 mmol NaOH

Thus, 4.800 mmol of H₃O⁺ were neutralized.

The initial amount of H₃O⁺ present was:

n = CV = (0.2000 mol/L)(25.00 mL) = 5.000 mmol H₃O⁺

The amount of H₃O⁺ that remains after addition of NaOH is:

(5.000 mmol) - (4.800 mmol) = 0.2000 mmol

The concentration of H₃O⁺ is the amount of H₃O⁺ divided by the total volume. The total volume is (25.00 mL) + (24.00 mL ) = 49.00 mL

C = n/V = (0.2000 mmol) / (49.00 mL) = 0.004082 M

The pH is finally calculated:

pH = -log([H₃O⁺]) = -log(0.004082) = 2.389

A well-insulated tank contains concentrated HCl solution in water. If more water is added to this tank the temperature of the system will __________.Select one:

a. increase

b. decrease

c. no change

d. cannot tell

Answers

Answer: Option (a) is the correct answer.

Explanation:

As the given situation shows that water is being added to water. This will liberate heat into the surround as the reaction will be exothermic in nature.

It is known that chemical reactions in which heat is released are known as exothermic reactions.

Hence, when more water is added to this tank the temperature of the system will increase due to release of heat.

Thus, we can conclude that if more water is added to this tank the temperature of the system will increase.

A cubic box with sides of 20.0 cm contains 2.00 × 1023 molecules of helium with a root-mean-square speed (thermal speed) of 200 m/s. The mass of a helium molecule is 3.40 × 10-27 kg. What is the average pressure exerted by the molecules on the walls of the container? (The Boltzmann constant is 1.38 × 10-23 J/K and the ideal gas constant is R = 8.314 J/mol•K .) (12 pts.)

Answers

Answer:

1.133 kPa is the average pressure exerted by the molecules on the walls of the container.

Explanation:

Side of the cubic box = s = 20.0 cm

Volume of the box ,V= s^3

V=(20.0 cm)^3=8000 cm^3=8* 10^(-3) m^3

Root mean square speed of the of helium molecule : 200m/s

The formula used for root mean square speed is:

\mu=\sqrt{(3kN_AT)/(M)}

where,

= root mean square speed

k = Boltzmann’s constant = 1.38* 10^(-23)J/K

T = temperature = 370 K

M = mass helium = 3.40* 10^(-27)kg/mole

N_A = Avogadro’s number = 6.022* 10^(23)mol^(-1)

T=(\mu _(rms)^2* M)/(3kN_A)

Moles of helium gas = n

Number of helium molecules = N =2.00* 10^(23)

N = N_A* n

Ideal gas equation:

PV = nRT

Substitution of values of T and n from above :

PV=(N)/(N_A)* R* (\mu _(rms)^2* M)/(3kN_A)

PV=(N* R* \mu ^2* M)/(3k* (N_A)^2)

R=k* N_A

PV=(N* \mu ^2* M)/(3)

P=(2.00* 10^(23)* (200 m/s)^2* 3.40* 10^(-27) kg/mol)/(3* 8* 10^(-3) m^3)

P=1133.33 Pa =1.133 kPa

(1 Pa = 0.001 kPa)

1.133 kPa is the average pressure exerted by the molecules on the walls of the container.

Final answer:

The question asks for the average pressure exerted by helium gas molecules on the walls of a cubic container. Using the equation PV = Nmv^2, we can calculate pressure by substituting the given values for volume, number of molecules, mass of one molecule, and root-mean-square speed.

Explanation:

The question is asking to calculate the average pressure exerted by helium gas molecules on the walls of a cubic container. The important formula relating pressure (P), volume (V), number of molecules (N), mass of a molecule (m), and the square of the rms speed (v2) of the molecules in a gas is:

PV = Nmv2,

First, we need to determine the volume of the container, which is the cube of one side, so V = (20 cm)3 = (0.2 m)3. Inserting the given values into the equation and solving for P gives us the desired answer. Recall that the rms speed is given, so no temperature calculations are needed.

Therefore, using all given data points:

Volume (V) = (0.2 m)3

Number of molecules (N) = 2.00 × 1023

Mass of one helium molecule (m) = 3.40 × 10-27 kg

Root-mean-square speed (vrms) = 200 m/s

By substituting these values, we can find the pressure exerted by the gas. This represents an application of kinetic theory of gases which assumes the behavior of an ideal gas.