MATHEMATICS HIGH SCHOOL

Quadrilateral ABCD is similar to Quadrilateral EFGH. The scale factor is 3:2. If AB = 18, find EF.

Answers

Answer 1
Answer:

Answer: EF = 12 units

Step-by-step explanation:

Given : Quadrilateral ABCD is similar to Quadrilateral EFGH.

The scale factor is 3:2.

We know that the scale factor is the ratio of the corresponding sides of two similar figures.

So if Quadrilateral ABCD is similar to Quadrilateral EFGH, the side AB corresponds to side EF.

If AB = 18, then we have the following equation:-

(AB)/(EF)=(3)/(2)\n\n\Rightarrow(18)/(EF)=(3)/(2)\n\n\Rightarrow\ EF=(2*18)/(3)\n\n\Rightarrow\ EF=12
Answer 2
Answer: EF =12

do you want to know how I got my answer...

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The slope of line m is 7/8. If n⊥m, what is the slope of line n? A) 7/8
B) 8/7
C) -7/8
D) -8/7

Answers

k:y=m_1x+b\nl:y=m_2x+c\n\nl\ \perp\ k\iff m_1m_2=-1
We have:
m_1=(7)/(8);\ m_2=?
Substitute:
(7)/(8)m_2=-1\ \ \ \ |\cdot(8)/(7)\n\nm_2=-(8)/(7)
Answer: D)
Hey there !

When two lines are perpendicular , the product of their slope is -1 ,

m1 × m2 = -1
7/8 × m2 = -1

m2 = -8/7 Ans.

how do I solve "at 1:00., you have 24 megabytes of a movie. at 1:15., you have 96 megabytes. what is the download rate in megabytes per minute?"​

Answers

Answer:

4 megabytes per minute

Step-by-step explanation:

Answer:

You're downloading 4.8 megabytes/minute.

Step-by-step explanation:

(96-24)/(15-0)=(72)/(15) =4.8

Larry has saved $18,500 toward a down payment on a house. If he makes $3,890 a month , how much can he afford to spend on house? A. 100,000
B. 93,369
C. 111,860
D. 65,180

Answers

Answer:  Option 'D is correct.

Step-by-step explanation:

Since we have given that

Amount he saved toward a down payment on a house = $18500

Amount he makes per month = $3890

Amount he makes in a year would be

3890* 12=\$46680

So, Amount he can afford to spend on house is given by

\$46,680+\$18,500\n\n=\$65,180

Hence, Option 'D is correct.

A map has a scale of 1 cm : 15.5 km. Two cities are 2.3 cm apart on the map. To the nearest tenth of a kilometer, what is the actual distance corresponding to the map distance?38 km
51.2 km
35.7 km
113.2 km

Answers

You will need to multiply 15.5 by 2.3. Keep in mind that this only works because the scale is 1cm but if it was say.... 3.4cm:15.5 you wouldn't be able to use that method. Yeah so the answer is 35.65 which rounds up to →35.7← because the second decimal place is five

Answer:

35.7km

Step-by-step explanation:

Which of the choices below best describes the domain and range of this problem. Domain would be tickets sold and range would be amount of money he collected. Elijah has already sold $40 worth of tickets for a local raffle. He has 5 tickets left to sell at $5 per ticket.

Answers

Answer:

Step-by-step explanation:

Amount of ticket sold = $40

If one ticket is $5, we need to know the amount of ticket he sold that fetched Elijah $40

$5 = 1ticket

$40 = x tickets

Cross multiply

5x = 40

x = 40/5

x = 8tickets

If he has 5tickets left to sell at $5 per ticket, the total tickets the sold will be 8+3 = 13 tickets

The domain of the problem will be [1, 13]

For the range:

The amount of the remaining 5tickets will be (5×$5) = $25

Initial amount made = $40

Total amount he collected = $25+$40

= $65

The range if the problem will be [$5, $65]

the ratio of apples to oranges on the fruit stand was 31:11 if there were 2,940 apples and oranges altogether, how many apples are there

Answers

First you add 31 and 11 and you get 42, then you do 2,940 divided by 42 which is 70. Then you multiply 70 by 31, and you get 2, 170, 
and there are 2,170 apples which is the answer
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