MATHEMATICS HIGH SCHOOL

Factor the GCF: −6m2 + 18m − 36.−6(m2 − 3m + 6)
−1(6m2 − 18m + 36)
−6m(m2 − 3m + 6)
−6(m2 + 3m − 6)

Answers

Answer 1
Answer: The first option is the right one.

You have to find the greates common divisor of the coefficientes, which is -6 and then divide each momomial with lead to: -6 (m^2 + -3m + 6).

You can verifiy the result by multiplying -6 times the polynomial inside the parenthesis, using the distributive property.
Answer 2
Answer:

Answer:

The first one is the right one i just took the test

Step-by-step explanation:

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Answers

Answer:

Justin does not have enough money because if you add up all the numbers you were given you get 155.82 and have 54.18 and the game costs 54.79. he is 61 cents off.

Step-by-step explanation:

choose the equation of the horizontal line that passes through the point (−2, −1) a. y = -1 b. y = - 2 c. x = -2 d. x = -1

Answers

(-2;\fbox{-1})\n\n\boxed{y=-1}\to\fbox{a.}

A closed container has 5.04 ⋅ 1023 atoms of a gas. Each atom of the gas weighs 1.67 ⋅ 10–24 grams.Which of the following shows and explains the approximate total mass, in grams, of all the atoms of the gas in the container?

Answers

Answer:

Step-by-step explanation:

Each atom of the gas weighs 1.67 ⋅ 10−24 grams. 6.71 grams, because (5.04 + 1.67) ⋅ (1023⋅ 10−24 ) = 6.71. ... 0.67 grams, because (5.04 + 1.67) ⋅ (1023⋅ 10−24 ) = 6.71 ⋅ 10−1.

Please someone answer this question as quick as possible please

Answers

Answer: 1/5 is the answer :)

What is the product of (x+1) and (2x^2+3x-1)?

Answers

(x + 1)(2x^2 + 3x - 1) : Can be solved in multiple ways but easiest for me :P

x (2x^2 + 3x - 1) + 1(2x^2 + 3x - 1)

(2x^3 + 3x^2 - x) + (2x^2 + 3x - 1)

2x^3 + 5x^2 + 2x - 1

X^2 + 3x - 18 = 0
Solve using the quadratic formula

Answers

x^2+3x-18=0\n\na=1;\ b=3;\ c=-18\n\n\Delta=b^2-4ac\to\Delta=3^2-4\cdot1\cdot(-18)=9+72=81\n\nx_1=(-b-\sqrt\Delta)/(2a);\ x_2=(-b+\sqrt\Delta)/(2a)\n\n\sqrt\Delta=√(81)=9\n\nx_1=(-3-9)/(2\cdot1)=(-12)/(2)=-6;\ x_2=(-3+9)/(2\cdot1)=(6)/(2)=3
x+6 and x-3 in which the absolute value would be if a positive 3 and a negative 6
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