Write the given sentence as an equation.Tim’s age in 7 years will be three times what it was 19 years ago.

A.)3(t + 19) = t – 7
B.)3(t + 7) = t – 19
C.)t + 19 = 3(t – 7)
D.)t + 7 = 3(t – 19)

Answers

Answer 1
Answer: D.)T+19=3(t - 7)
hope it helped

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Sin78 ×cos42+cos78×sin42 evaluate without the use of a calculator

Answers

sin a * cos b + cos a * sin b=sin (a+b)

sin 78 * cos 42 + cos 78* sin 42=sin (78+42)=sin 120=sin(180-120)=
sin 60=√3 / 2

Answer: sin 78 * cos 42 + cos 78* sin 42=√3 / 2

Which graph correctly solves the system of equations below?x2 + y2 = 9
y = x + 3

Linear graph and circle. They intersect at negative 3, 0 and 0, 3
Linear and a quadratic graph. They intersect at negative 3, negative 5 and 2, 0.
Linear and a quadratic graph. They intersect at negative 2, 0 and 1, 3.
Linear graph and circle. They intersect at negative 2, 0 and 0, 2.

Answers

x^2 + y^2 = 9 . . . . . . . .  circle
y = x + 3 . . . . . . . (linear graph)

They intersect at (-3, 0) and (0, 3)

Answer:

They intersect at (-3, 0) and (0, 3)

Step-by-step explanation:

took the test hope it helps

Find the inverse of each function1) g (x)= 3+(x-1)^3
4) f (x)=x^3+2
5) f (n)= 5 square root of (-n+1/2)

Answers

to find the inverse
1. replace f(x) or g(x) or f(n) with y
2. switch places of x and y
3. solve for y
4. replace y with f⁻¹(x) or g⁻¹(x) or f⁻¹(n)



1.
g(x)=3+(x-1)^3
replace
y=3+(x-1)^3
switch
x=3+(y-1)^3
solve
x=3+(y-1)^3
subtract 3
x-3=(y-1)^3
cube root both sides
\sqrt[3]{x-3}=y-1
add 1
\sqrt[3]{x-3}+1=y
switch y with g⁻¹(x)
g⁻¹(x)=\sqrt[3]{x-3}+1





4. f(x)=x^3+2
replace with y
y=x^3+2
switch x and y
x=y^3+2
solve for y
x=y^3+2
subtract 2
x-2=y^3
cube roo both sides
\sqrt[3]{x-2}=y
replace with f⁻¹(x)
f⁻¹(x)=\sqrt[3]{x-2}



5.
f(n)=5√(-n+1/2)
replace
y=5√(-n+1/2)
switch n and y
n=5√(-y+1/2)
solve for y
n=5√(-y+1/2)
divide both sides by 5
n/5=n=√(-y+1/2)
square both sides
(n^2)/(25)=-y+1/2
subtract 1/2 from both sides
(n^2)/(25)-(1)/(2)=-y
multiply both sides by -1
-(n^2)/(25)+(1)/(2)=y
replace with f⁻¹(n)
f⁻¹(n)=-(n^2)/(25)+(1)/(2)



1.  g⁻¹(x)=\sqrt[3]{x-3}+1
4.  f⁻¹(x)=\sqrt[3]{x-2}
5.  f⁻¹(n)=-(n^2)/(25)+(1)/(2)











A 3 pound package of ground beef sells for $6. At this rate, if John buys 10 pounds ofground beef, how much would he pay?

Answers

Answer:

$20

Step-by-step explanation:

3 pounds of beef is 6 dollars.

6 divided by 3 is 2. Therefore, each pound cost $2.

He wants to buy 10 pounds of beef.

9 pounds would be $18.

Add 1 pound, which is $2 and you will get $20.

Therefore, he would pay $20!~

Hope this helps!~~ <3

7x-8x+4=5x-2 solve for x

Answers

7x - 8x + 4 = 5x - 2

7x - 8x - 5x = -2 - 4

-6x = -6

x = 1
7x-8x+4=5x-2 \n 4+2=5x-7x+8x \n 6=6x \n 6/6=x \n 1=x

What is the monthly payment of a financed amount of $14,452 with an APR of 8.9 percent? The term is for 5 years and the monthly payment per $100 is $2.41. $332.80 $348.29 $100.00 $241.00

Answers

Answer:

$348.29

Step-by-step explanation:

The payment is calculated by multiplying the rate per hundred times the number of hundreds. The latter is found by dividing the loan amount by $100.

$2.41 × $14,452/$100 ≈ $348.29

Answer:$299.16

 

Step-by-step explanation:

Financed amount = $14452

APR  = 8.9%

Period / time = 5 years

monthly payment = $100 for every $2.07

To calculate the monthly payment of a financed amount we multiply the financed amount by the ratio of the given amount paid per $100

The monthly payment would be =  14452 * 2.07/100 = 14452 * 0.0207

= $299.16 approximately

therefore the monthly payment of a financed amount of $14452 is equal to $299.16