MATHEMATICS MIDDLE SCHOOL

Quadrilateral ABCD is an isosceles trapezoid with AB || CD If Angle D= 70 degrees, which statement is false? A. angle C=70
B. angle C=110
C.angle B=110
D.angle A=110

Answers

Answer 1
Answer:

For the quadrilateral ABCD if Angle D=70 then the angle A cannot be equal to 110 if AB II CD .

What is an isosceles trapezoid?

It is a trapezoid in which the base angles are equal and the left and right side lengths are equal.

How to calculate angles?

In an isoceles trapezoid the angles made by the base  are equal. So if AB II CD and the angle D is 70then the angle C will be 70, Angle B will be 180-70=110 and angle A will be 180-110=70.

Hence the correct option for the given question will be option D.

Learn more about isoscelestrapezoid at brainly.com/question/8644421

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Answer 2
Answer: i think it is d angle a=110

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Two numbers have a sum of 99. If one number is p, express the other number in terms of p.

Answers

Answer:

Step-by-step explanation:

p+p=99

2p=99

p=99/2

PROBLEM #1Keith has $500 in a savings account at the beginning of the
summer. He wants to have at least $200 in the account by the
end of summer. He withdraws $25 a week for his cell phone
bill.
Write an inequality that represents Keith's situation.

Answers

Answer:

  • 500 - 25w ≥ 200

Explanation:

Translate every verbal statement into an algebraic statement,

1. Keith has $500 in a savings account at the beginning of the summer.

  • Initial amount: 500

2.  He wants to have at least $200 in the account by the end of summer.

  • Final amount ≥ 200

3. He withdraws $25 a week for his cell phone bill.

  • Call w the number of weeks
  • Withdrawls = 25w

4. Write an inequality that represents Keith's situation.

  • Create your model: Final amount = Initial amount - withdrawals ≥ 500

  • 500 - 25w ≥ 200

With that inequality you can calculate how many week will pass before his account has less than the amount he wants to have in the account by the end of summer:

  • 500 - 200 ≥ 25w
  • 300 ≥ 25w
  • 300/25 ≥ w
  • 12 ≥ w
  • w ≤ 12

That represents that he can afford spending $ 25 a week during 12 weeks to have at least $ 200 in the account.

1/6+(-2/3)= a.-4/6
b.1/2
c.-1/2
d.-5/6


plz only abitious and up

Answers

1/6+ (-2/3)
= 1/6 - 4/6
= -3/6
= -1/2

The correct answer is c. -1/2~
you can say -2/3 = -4/6 so : 1/6 - 4/6 = -3/6 = -1/2 and thats the simplest so the answer is c :))
i hope this is helpful
have a nice day 

Line segment AB has endpoints A(2, 9) and B(5, 8) . A dilation, centered at the origin, is applied to AB¯¯¯¯¯ . The image has endpoints A′(43, 6) and B′(103, 163) . What is the scale factor of this dilation? 32
23
2
3

Answers

Answer:  The correct option is (B) (2)/(3).

Step-by-step explanation:  Given that the co-ordinates of the end-points of a line segment AB are A(2, 9) and B(5, 8). After being dilated about the origin (0, 0), the co-ordinates of the end-points of image A'B' are A^\prime\left((4)/(3),6\right) and B^\prime\left((10)/(3),(16)/(3)\right).

We are to find the scale factor of the dilation.

The scale factor of the dilation will be

S=\frac{\textup{length of the image line}}{\textup{length of the original line}}.

The lengths of the lines AB and A'B' are calculated using distance formula as follows:

AB=√((5-2)^2+(8-9)^2)=√(9+1)=√(10),\n\n\nA'B'=\sqrt{\left((10)/(3)-(4)/(3)\right)^2+\left((16)/(3)-6\right)^2\right)}=\sqrt{4+(4)/(9)}=\sqrt{(40)/(9)}=(2)/(3)√(10)~\textup{units}.

Therefore, the required scale factor of dilation is

S=(A'B')/(AB)=((2)/(3)√(10))/(√(10))=(2)/(3).

Thus, the scale factor of the dilation is (2)/(3).

Option (B) is CORRECT.
the answer is 2/3 
i took the test
hope this helps!

Liam bought 5 7/8 pounds of steak. He used 2 1/16 pounds of the steak for a cookout. Liam has about how many pounds of steak remaining after the cookout?

Answers

Liam bought a total of 5 7/8 pounds of steak. Then he used 2 1/16 pounds of steak for a cookout.Given with the data above, let's find out how many pounds were left after he used some of it.=> Notice that the given numbers are fractions> => 5 7/8 pounds and 2 1/16 poundsSince these are mixed fraction, let's convert it to improper fraction. => 5 7/8 = (8 * 5 = 40 + 7 = 47) = 47 / 8=> 2 1/16 = (16 * 2 = 32 + 1) = 33 / 16The equation is now = 47/8 - 33/16=> Since they don't have the same denominator, let's find the lCD=> 47/8 - 33/16 = 94/16 - 33/16 = 61/16Let's change it to mixed fractions=> 61 /16 = 3.8 or => 3 . 8/100 = 3 2/25

Answer:

hell

Step-by-step explanation:

nothing

Help pleeeaaseWhat is the best approximation of the solution to the system to the nearest integer values?



A.
(1, 3)

B.
(3, 2)

C.
(2, 3)

D.
(3, 4)

Answers

C. (2,3) The solution to the system of equations is where the two lines will intersect. looking at the graph that point is closest to C. (2,3)
5x + 2y = 16 ⇒ 5x + 2y = 16
  x + 3y = 12 ⇒ 5x + 15y = 180
                                -13y = -164
                                 -13      -13
                                     y = 12 8/13
               5x + 2(12 8/13) = 16
                   5x + 25 3/13 = 16
                          -25 3/13   -25 3/13
                                   5x = -9 3/13
                                    5          5
                                     x = -1 11/13
                               (x, y) = (-1 11/13, 12 8/13)
B. (3, 2)
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