How to find the answer of -√(652)
Answers
-25.5????????????
This could be wrong but I tried..
Sorry : /
Related Questions
A number increased by 10 is 114 answer in an equation
AC = 4, AE = 7, AD = 10, what is the length of AB? PLZ HELP
Gina was earning $10 per hour. THen she recieved a 10% pay increase. Next month, her pay rate will decrease by 10%. What will Gina's pay rate be next month? a. $10.10 per hour b. $12.10 per hour c. $9.90 per hour d. $10.00 per hour. Im thinking it would be c or d. PLEASE EXPLAIN?!
24 is what percent of 800
Answers
f(1) = 8 => a + b = 8;
f(2) = 14 => 2a + b = 14 => a = 6 and b =2;
f(3) = 20 => 6*3 + 2 = 20 True;
f(4) = 26 => 4*6 + 2 = 26 True;
then, f:R -> R, f(x) = 6x + 2;
Answers
Answers
Answer: 80
If its within 1 2 3 or 4 you round down, so if our number was 73, the nearest whole number would be 70.
Our question here consist of 76.78.
Well just by looking at the first part of the number, 76, we already know that we are rounding up. so in doing this, I was able to get 80 because when 5 6 7 8 or 9 you round up.
Answers
Answer:
8,000 in the 8% account
20,000 in the 9% account.
Step-by-step explanation:
x + y = 28000
0.08 x + 0.09 y = 2440
0.08 x + 0.09 (28000 − x) = 2440
0.08 x + 2520 − 0.09 x = 2440
80 = 0.01 x
x = 8000
y = 20000
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Answer:
The variables represented in an addition or subtraction equation expression is the letter associated with a number, it acts as a place holder for that unknown value that is multiplyed by the coefficient or number infront of the letter.
Answers
Answer:
Equation 3
Step-by-step explanation:
Lets see which of the functions has -2 as a zero root. We will go in order:
(1) (-2)^4 - 3(-2)^3 + 3(-2)^2 -3(-2) + 2 = 16 - 3(-8) + 3(4) + 6 +2 = 16 +24 +12 + 6 +2 =60 >0
So, (1) is wrong!
(2) (-2)^4 + 3(-2)^3 + 3(-2)^2 - 3(-2) - 2 = 16 - 24 + 12 + 6 - 2 =34 - 26 = 8 > 0
(2) is also wrong!
(3) (-2)^4 + 3(-2)^3 + 3(-2)^2 +3(-2) + 2 = 16 - 24 + 12 - 6 + 2 = 30 -30 = 0
The zero root x=-2 fits, what about x=-1?
(-1)^4 + 3(-1)^3 + 3(-1)^2 +3(-1) + 2 = 1 - 3 + 3 - 3 + 2 = 6 - 6 = 0
So, equation (3) fits both!
Finally, lets see (4):
(-2)^4 - 3(-2)^3 - 3(-2)^2 + 3(-2) + 2 = 16 + 24 - 12 - 6 + 2 = 42 - 18 = 24 > 0
So, (4) is also wrong.
Only equation 3 fits both zero roots!
Final answer:
The quartic function with x=-1 and x=-2 real roots is x^4+6x^3 +12x^2+12x+4. Quartic functions are polynomial functions of degree 4; quadratic equations resources also help understand the concept. In essence, finding roots of quartic functions follow the same logic as that of quadratic functions.
Explanation:
The subject matter pertains to quartic functions in mathematics. Quartic functions are polynomial functions with a degree of 4. From the question, the given zeros are x=-1 and x=-2, having multiplicity of 2 each (since there are only two real zeros). Thus, the quartic function with these zeros will be (x+1)^2*(x+2)^2. This can be expanded to x^4+6x^3 +12x^2+12x+4.
Exemplifying the relevance of The Solution of Quadratic Equations, normally known as second-order polynomials or quadratic functions, such equations can also be used to find zeros of the functions when set to equal zero. In this scenario, quartic functions are a degree higher, but the same principle applies in finding the roots when the equation is set equal to zero.
Learn more about Quartic Functions here:
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