How do you find rhe slope of (12,-18) and (-15,-18)

Answers

Answer 1

Answer: slope of 2 points is
if you has the points
(x1,y1) and (x2,y2)

slope=(y2-y1)/(x2-x1)

we are given
(12,-18)
(-15,-18)

we can either take shortcut and recocnize that -18-(-18)=0 so that make the slope 0

or we can continue
(-18-(-18))/(-15-12)=0/-27=0

slope=0

Answer 2

Answer: you do Y2-Y1/ X2-X1, so -18--18(change sighn so it would be -18+18) which equals 0, then -15-12= -27, 0/-27= 0 so the slope would be 0

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Write an equation of a line that has the same slope as 2x – 5y = 12 and the same y-intercept as 4y + 24 = 5x.y = 1/6x - 5/2
y = 2/5x - 6
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y = 5/2x - 6

Answers

in ax+by=c form
slope=-a/b

y intercept is when x=0

sloope of 2x-5y=12 is -2/-5=2/5

y intercept of 4y+24=5x
4y+24=5(0)
4y+24=0
4y=-24
y=-6
y int=-6

y=mx+b
m=slope
b=y intercept
y=2/5x-6

answer is 2nd optoin

Of 60 students in a class 2/3 are girls, and 2/5 of the class are taking music lessons. What is the maximum number of girls that are not taking music lessons?

Answers

24 girls. Because 60/3=20 20*2=40. So than u do 40/5=8 8*2=16 40-16=24.

What is the range of the function below in set builder notation? y=|x-3|

Answers

Answer: $\{y | \ y \in \mathbb{R}, \ y \ge 0\}$

This translates to "y is any real number such that it is 0 or larger".

The reasoning is that the result of any absolute value function is either 0 or positive. In other words, we'll never get a negative result of an absolute value function. This is due to how absolute value represents distance. Negative distance does not make sense.

So if y = |x-3| then y = 0 is the smallest output possible. We could have any positive output we want.

In terms of a graph (see below), the V shape is at the lowest point (3,0). The y coordinate is all we care about in terms of finding the range. So we see the lowest y value is y = 0.

If m is the midpoint of xy find the coordinates of x if m -3,-1 and y -8,6

Answers

Answer:

To find the coordinates of x, we can use the midpoint formula, which says that the midpoint of a line segment is the average of the x-coordinates and the y-coordinates of the endpoints12. That is:

m=(2x1+x2,2y1+y2)

In this case, we know that m is (−3,−1) and y is (−8,6). We can plug these values into the formula and solve for x:

(−3,−1)−3−6x−1−2−8=(2x+(−8),2−1+6)=2x−8=x−8=2=2−1+6=−1+6=6

Therefore, x is (2,−8). You can check your answer by plugging it back into the midpoint formula and see if you get m.

I hope this helps

Step-by-step explanation:

How do u find the slope of this lol