is 6 ft off the ground. How high is the kite? Round your answer to the nearest
tenth
The height of the kite from the ground is 270 feet.
There are three commonly used trigonometric identities.
Sin x = 1/ cosec x
Cos x = 1/ sec x
Tan x = 1/ cot x or sin x / cos x
Cot x = cos x / sin x
We have,
B
/ |
300 ft / |
/ |
/ |
/ |
A_62°___________|C
|
| 6 feet
E|________________D
Now,
Sin 62° = BC/AB
0.88 = BC/300
BC = 0.88 x 300
BC = 264 ft
Now,
The height of the kite from the ground.
= BC + CD
= 264 + 6
= 270 ft
Thus,
The height of the kite from the ground is 270 feet.
Learn more about trigonometricidentities here:
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Answer:
270.9 ft
Step-by-step explanation:
6 + 300sin(62)
= 270.8842779 ft
5+−
1
5
3
5+−
1
5=two fifths
2
5 (Type an integer or a fraction.)
Answer:
Calculator soup has a calculator that can do that
Step-by-step explanation:
Answer:
$233.2
Step-by-step explanation:
0.06x220=13.2
220+13.2=233.2
Answer:
$233.20
Hope I could help you out!
Please explain how you broke it up and did
See attached image.
I broke it up into 4 different shapes, 3 triangles and a square.
Area for a triangle is 1/2 x base x height:
Triangle 1: 1/2 x 4 x 3 = 6
Triangle 2: 1/2 x 6 x 3 = 9
Triangle 3: 1/2 x 1 x 6 = 3
Area of square = S^2 = 6^2 = 36
Total area = 36 + 6 + 9+3 = 54 square units
Draw a segment from point E to point B. Now you have a triangle above with base FB of length 10 and height EA of length 3, and a trapezoid below with bases DC of length 7 and EB of length 6 and height CB of length 6.
area of figure = area of triangle + area of trapezoid
area of figure = bh/2 + (b + b)h/2
area of figure = 10(3)/2 + (7 + 6)(6)/2
area of figure = 15 + 39
area of figure = 54