A number decreased by 5 is less than 32

Answers

Answer 1

Answer: To find the answer to this question, we need to set up a simple inequality. Let's use n to represent the number we're looking for, and, since the number is less than 32, we'll use the < symbol.

n - 5 < 32 A number decreased by 5 is less than 32
n < 37 Add 5 to both sides

Therefore, the number is less than 37. It could be 36 or lower.

Hope this helps!

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Answers

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Which of the following statements is true about the three quadrilaterals?O M and O are similar and congruent.
O O and N are similar and congruent.
OM and N are similar but not congruent.
OM and O are similar but not congruent.

Answers

Answer:

Step-by-step explanation:

Describe four real-life situations in which you might need to add or subtract decimals.

Answers

If youre a cashier
if youre a mathematician
if you have to pay taxes and bills
if your have to loan something

1. If you're shopping and your total becomes 12.98
2. Calculating measures for your job
3. Measuring for cooking 2.5 (2/5) sugar.
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the sides of a triangle have lengths of x, x+5, and 25. if the longest side is 25, which of the following values of x would make the right triangle?

Answers

$x^2+5x-300=0 \n \n \Delta =b^2-4ac =5^2 -4*1* (- 300)= 25+1200=1225 \n \nx_(1)=(-b- √(\Delta ) )/(2a)=(-5- √(1225))/(2 )=(-5-35)/(2)=-(-40)/(2)=-20 \n\n \ side \ not \ can \ also \ be \ negative$

$x_(2)=(-b+ √(\Delta ) )/(2a)=(-5+ √(1225))/(2 )=(-5+35)/(2)=-(30)/(2)=15\n \nAnsewr : \ x= 15$

ALGEBRA HELP, please help with problem, and show work

Answers

First of all, your second term is already wrong. When you divided 8x² by 4 ,
you should have written 2x² , not 4x² .

Make that correction, and then divide the whole thing by 'x'.

Then you'll have x² - 2x + 1 = 0 .

You should have no trouble solving that one,
(especially since it's a perfect square)

That gives you two (equal) solutions. But you should also ask yourself:
"Self ! Where is the third solution ? A cubic equation like the original
one needs three solutions."

I'll give you that one:
Look over the original equation, and look at what happens to it when x = 0 .
Then the left side becomes zero, and the equation is 0 = 0 . Since that's a
true statement, " x = 0 " is another solution of the cubic equation, and now
you have all three of them.

divide both sides by 4x:
x^2-2x+1=0
You can either factor, complete the square, or use the quadratic formula.
I'll factor this into (x-1)(x-1)=0
x-1=0, so x=1

Solve for b if 7+16b=29+5b

Answers

7 + 16b = 29 + 5b

Keep the variables on one side

16b - 5b = 29 - 7

11b = 22

Divide by 11 isolate b:

$(11b)/(11)$ = $(22)/(11)$
11 and 11 cancels out

b = 2

check:
7 + 16(2) = 29 + 5(2)
7 + 32 = 29 + 10
39 = 39

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