Please answer question number four thank you!
Please answer question number four thank you! - 1

Answers

Answer 1
Answer: 26( w times w times w less than nvm its less than


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For each of the transactions in items 1 through 5, indicate the effects on the accounting equation elements. The company purchases equipment with cash- The Equity account does the following

A. Increase
B. Decrease
C. No effect

Answers

Answer:

Decrease I think.

Sorry if it is wrong.

Hope it helped :)

14. teacher needs 70 lengths of string cut to 40 cm each. If balls of string are 10m longhow many balls will be needed.

Answers

70×40=2800cm which is the total amount of cm that the teacher needs

10m = 1000cm 

(2800)/(1000) = 2.8

there will be 3 balls of string
70×40=2800 cm, which would be the total amount of cm that the teacher needs for the balls.

10m = 1000cm 

 = 2.8

There will be 3 balls of string.

Solve the following system of equations graphically on the set of axes below. y=2x−5. 3x+4y=24

Answers

Answer:

all work is shown and pictured

one year, the attendance at the super bowl was 79,401. the following year, attendance was 85,916 use words to explain the relationship between the digit 9 in 79,401 and the digital 9 in 85,916

Answers

The 9 digit is in the ten thousand place.The ten thousand place is less than hundred thousand , and it's greater than one thousand , hundred place , ten place ,and the ones place.

What is the area of the triangle? A. 26.91 cm² B. 28.98 cm² C. 53.82 cm² D. 57.96 cm²

Answers

A= hᵇb
       2
hope that helped at all.

At 1:00 pm the water level in a pool is 13 inches. At 1:30pm the water level is 18 inches. At 2:30pm the water level is 28 inches. What is the constant rate of change?

Answers

From the given question we come to know of certain number of facts and they are:
At 1:00 PM the water level of the pond was = 13 inches
At 1:30 PM the water level of the pond was = 18 inches
At 2:30 PM the water level of the pond was = 28 inches
From the above given facts we can easily find the amount of water changing every half an hour.
Amount of increase in water from 1:00PM to 1:30 PM = (18 - 13) inches
                                                                                       = 5 inches
Amount of increase in water level from 1:30PM to 2:30PM = (28 -18) inches
                                                                                             = 10 inches
From the above two deductions we can come to the conclusion the the constant rate of change in water level is 5 inches for every half an hour.
Per 1/2 an hour it is changes by 5 so the constant rate would be: 5 inches per 1/2 an hour