Bob had 18 crackers Sam eat 1/6 of the crackers and sue ate 1/3 of the crackers. how many crackers did Bob have left

Answers

Answer 1

Answer: We can add 1/6 & 1/3 together to find out the total amount of crackers that were eaten:

1/6 + 1/3 (Find the Common Denominator. In this case it is 6.)
= 1/6 + 2/6
= 3/6 (Now find the Lowest Terms. Both 6 & 3 divide into 3)
= 1/2 (In Lowest Terms)

This means that 1/2 of the Crackers have been eaten.

1/2 of 18 = 9

Therefore, Bob has 9 Crackers left.

Answer 2

Answer: The first thing to do is make both fractions over 6:
1/3 = 2/6
Sue at 2/6 of the crackers.

Now we can add the fractions:
2/6 + 1/6 = 3/6

The next thing to do is cancel down the fraction.
3/3 = 1
6/3 = 2
3/6 = 1/2

Now that we know that half of the crackers have been eaten, we halve the total amount:
18 X 1/2 = 18 / 2 = 9

Bob had 9 crackers left.

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