Answer: surface area = 108.8 sq. cm
Step-by-step explanation:
A=πr(r+√h2+r2)
Answer:
108.8cm^2
Step-by-step explanation:
Surface Area
A = πr(r+ √h2+r2)
A= π3 * (3 +1/3) √64 + 9 (+ 3) = sqroot 17 +3 = 20 + (3 x 4) = π32
A= 108.7
Volume
V=πr2h/3
V= π9*8 = π72/3 = 226.28/3
V= 72.4cm^3
Additional
The cone has a radius of 3cm and height of 8cm, find total surface area of the cone.
To begin with we need to find slant height of the cone, which is determined by using Pythagoras, since the cross section is a right triangle.
l2 = h2 + r2
l2 = 64 + 9
l = √(73)
l = 8.54 cm
And the total surface area of the cone is:
SA = πr2 + πrl
SA = π · r · (r + l)
SA = π · 3 · (3 + 8.54)
SA = π x 3 . 11.54
SA = 9.42477796077 x 11.54 = 108.76 cm2
SA = 108.8cm^2
Answer:
300 pages of arithmetic and 180 pages of geometry
Step-by-step explanation:
Given,
The ratio of arithmetic content and geometric content = 5 : 3
Let the pages in arithmetic contents = 5x,
And, the pages in geometric content = 3x,
Where, x is a positive real number,
So, the total pages = 5x + 3x = 8x
According to the question,
8x = 480
⇒ x = = 60
Hence, the content of arithmetic = 5 × 60 = 300 pages,
While, the content of geometry = 3 × 60 = 180 pages,
Answer:
meaningless
Step-by-step explanation:
Answer:
Find the median: (the middle number in the data set).
Find both the upper and lower quartile.
The subtract the upper quartile to the lower quartile, and you get the final answer of an interquartile range.