Calculate the decrease in temperarure when 2.00 L at 20.0 degrees celsius is compressed to 1.00 L.

Answers

Answer 1
Answer: I suspect that the pressure of this change is constant therefore

The equation is used from the combined gas law. (When pressure is constant both P's will cancel out P/P = 1)
V/T = V/T
Initial   Change

Initially we have 2L at 20 degress what temperature will be at 1L.

2/20 = 1/T
0.1 = 1/T
0.1T = 1
T = 1/0.1
T = 10 degress celsius.

Hope this helps if you won't be able to understand what is the combined gas law just tell me :).
Answer 2
Answer:

Final answer:

Using Charles's law, the calculation indicates a decrease in temperature by about 146.58 degrees Celsius when a 2.00 L volume of gas at 20.0 degrees celsius is compressed to 1.00 L.

Explanation:

To calculate the decrease in temperature due to compression, we can utilize Charles's Law, provided we are ignoring any changes in pressure. Initially, we have a volume (V₁) of 2.00 L at a temperature (T₁) of 20.0 degrees celsius which is equivalent to 293.15 K (converting to Kelvin). The volume is then compressed to 1.00 L (V₂) and we need to find the new temperature (T₂).

According to Charles' Law (V₁/T₁ = V₂/T₂), after we input the values from the problem, we can isolate T₂, resulting in following equation: T₂ = (V₂* T₁)/ V₁. Substituting the given values, we get T₂ = (1.00L*293.15 K)/2.00 L = 146.57 K.

However, we want to find the decrease in temperature in celsius. Difference in temperature in Celsius and Kelvin scales are the same. So, the decrease in temperature (ΔT) = T₁ - T₂ = 20.0°C - (-126.58°C) = 146.58°C. So, when the volume of the gas is compressed from 2.00 L to 1.00 L, the temperature decreases by about 146.58 degrees Celsius.

Learn more about Charles's Law here:

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I just took the quiz and got it Correct.

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Answers

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Hope this helps~
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Answers

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Answers

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