Conrad has a collection of three types of coins: nickels,dimes,and quarters.There are five more nickels than quarters but four times as many dimes as quarters.If the entire collection is worth $5.85,how many nickels,dimes,and quarters are there?

Answers

Answer 1
Answer: n=number of nickles
d=number of dimes
q=number of quarters
use cents for everything

total value=585
5n+10d+25q=585
divide everybody by 5 to simplify
n+2d+5q=117

we have

nicles are 5 more than quarters
n=5+q

4 times as many dimes as quarters
d=4 times q
d=4q

sub those in
5+q+2(4q)+5q=117
5+6q+8q=117
5+14q=117
minus 5
14q=112
q=8

sub back
n=5+q
n=5+8
n=13

d=4q
d=4(8)
d=32


13 nickles
32 dimes
8 quarters
divide both sides by 22


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Determine the measures of ∠ L and ∠ M . The figure shows a triangle UpperWord LMN. Sides UpperWord MN and UpperWord LN of this triangle are produced to points Upper O and Upper P respectively. The angle UpperWord ONP is labeled as 48 degree, angle UpperWord NLM is labeled as x, and the angle UpperWord LMN is labeled as x.

Answers

The measures of ∠ L and ∠ M are 180 degrees - x and 132 degrees - x, respectively.

Since the interior angles of a triangle add up to 180 degrees, we have the following equation:

x + x + L + M = 180 degrees

We also know that the exterior angle of a triangle is equal to the sum of the two non-adjacent interior angles. Therefore, we have the following equation:

L = x + 48 degrees

We can substitute this equation into the first equation to get:

x + x + x + 48 degrees + M = 180 degrees

Combining like terms, we get:

3x + 48 degrees + M = 180 degrees

Subtracting 48 degrees from both sides, we get:

3x + M = 132 degrees

Subtracting x from both sides, we get:

2x + M = 132 degrees - x

We can now substitute this equation into the equation L = x + 48 degrees to get:

L = (132 degrees - x) + 48 degrees

L = 180 degrees - x

Therefore, the measures of ∠ L and ∠ M are 180 degrees - x and 132 degrees - x, respectively.

For such more question on degrees

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Final answer:

In triangle LMN, both angle L and angle M are 24 degrees, calculated using the property of exterior angles in triangles.

Explanation:

From your question, it seems like we're dealing with an issue of triangle geometry and exterior angles in particular. In a triangle, the measure of an exterior angle is equal to the sum of the measures of the two non-adjacent interior angles. This means, in triangle LMN, angle ONP (which is 48 degrees) equals to the sum of angle NLM (which is x) and angle LMN (also x).

Therefore, we can make the equation as 2x = 48, where 2x accounts for angles NLM(x) and LMN(x). Solving this equation gives us x = 24. Hence, ∠L (or NLM) = 24 degrees and ∠M (or LMN) = 24 degrees.

Learn more about Triangle Geometry here:

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27x^3+9x^2-3x-2 /3x-2

Answers

Answer:

(27x3+9x2-3x-10)/(3x-2)  

Final result :

 9x2 + 9x + 5

Step by step solution :

Step  1  :

Equation at the end of step  1  :

 

Step  2  :

Equation at the end of step  2  :

 

Step  3  :

           27x3 + 9x2 - 3x - 10

Simplify   ————————————————————

                  3x - 2        

Checking for a perfect cube :

3.1    27x3 + 9x2 - 3x - 10  is not a perfect cube  


25% of what number is 15

Answers

since 25% is 1/4 of 100% then you do 4 times 15 and that equals 60.
15 is 25% of 60
hopes this helps :) :D :)

Explain why P(A|D) and P(D|A) from the table below are not equal.

Answers

Answer:

The two conditional probabilities are not equal because each has different given events. P(A|D) has event D as its given event, resulting in 2/10 for a probability. P(D|A) has event A as its given event, resulting in 2/8 for a probability.

Other part is:

different given events

P(A|D) equals 2/10

P(D|A) equals 2/8

because they are in different positions which make them different answers/number

7/10+6/100=

how do solve this problem


Answers

We need to find the Lowest Common Denominator = LCD lowest is 100
10 x 10, 20, 30, 40, 50, 60, 70, 80, 90, 100
100 x 100, 200, 300, 400, 500, 600, 700, 800, 900, 1000. which is the lowest and common? 100
7/10  /100 how many times can 10 go into 100? 10 times. so we will multiply 10 time the numerator which is 7, and now will be 70/100
6/100 /100 how many times can 100 go into 100? 1 time. so we will multiply 1 time the numerator 6 which equals 6. 6/100
now add the new fractions. 70/100 + 6/100 = 76/100
(7)/(10)+(6)/(100)=(70)/(100)+(6)/(100)=(76)/(100)=0.76

an ecosystem which is 10 km squared contains a population of 1000 squirrels what is the population density of the squirrels in this ecosystem

Answers

Answer:

100 squirrels/km^2

Step-by-step explanation:

we know that

To find the population density of the squirrels in the ecosystem, divided the quantity of population of squirrels by the area of the ecosystem

so

1,000/10=100 squirrels/km^2