Answer:
C.
Explanation:
Molecules with the stronger intermolecular forces are pulled tightly together to form solid at higher temperatures and that's why the freezing point is higher.
Also, molecules with the stronger intermolecular force have greater interaction between the molecules and thus on heating do not boil easily and have high boiling point also.
Thus, melting point and boiling point increases with increase in number of carbon atoms and also increase in intermolecular forces (like hydrogen bonding, if present).
Thus, the compound which is gas at room temperature is because it has least number of carbon atoms and absence of hydrogen bonding.
Among the choices, only CH3CH2CH3 (propane) is a gas at room temperature. The other compounds, CH3CH2OH (ethanol), CH3CH2CH2CH2CH2CH2CH3 (hexane), and HOCH2CH2OH (ethylene glycol) are all liquids.
Among the four compounds given, compound C, which is CH3CH2CH3 (also known as propane), is a gas at room temperature. Compound A (CH3CH2OH, or ethanol), compound B (CH3CH2CH2CH2CH2CH2CH3, or hexane), and compound D (HOCH2CH2OH, or ethylene glycol) are all liquids at room temperature.
The state of a compound at room temperature depends on factors like molecular mass and intermolecular forces. Propane has a smaller molecular mass and weaker intermolecular forces than the others, making it a gas at room temperature.
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Answer:
please check image and explanation
Explanation:
First write the balance chemical reaction
CO(g)+2H2(g)⇌CH3OH(g)
To find out the equilibrium constant first need to find the concentration of each entities at equilibrium.
Rest all thing in the image
True
False
Answer:
This is true.
Explanation:
Answer:
Its 7
Explanation:
I took the test...
Answer:
The equilibrium will shift to the reactants and increase the concentration of CH3COOH
Explanation:
According to Le Chatelier's principle when a system at equilibrium is subjected to a change in temperature, pressure, concentration etc then the equilibrium will shift in a direction to undo the effect of the induced change.
The given reaction is:
CH3COOH ↔ CH3COO-(aq) + H+(aq)
CH3COONa exists as ions i.e. CH3COO- and Na+. Therefore, addition of CH3COONa will introduce more CH3COO- ions into the system as a result the equilibrium will shift to the left i.e. towards the reactants and will produce more of CH3COOH
The smallest possible particle of an element is a atom. An electron has a charge identical to that of of a proton, but with the opposite sign.
The smallest unit of matter that may be split without producing electrically charged particles is the atom. It is also the smallest piece of substance with chemical element-like characteristics. Electric forces, which link electrons towards the nucleus of atoms, cause them to be drawn to any positive charge.
Space makes up the majority of an atom. The remainder is made up of a cloud of negatively charged electrons around a positively charged nucleus made up of protons and neutrons. An electron has a charge identical to that of of a proton, but with the opposite sign.
Therefore, an electron has a charge identical to that of of a proton, but with the opposite sign.
To learn more about atom, here:
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