Hi Lisa
x³ + 2x² - 15x
= x( x-3)(x+5)
I hope that's help:)
Have a great summer :)
solve for x
B=x9 + 1
C=81x3 + 16x6
D=x6 + x3
E=27x9 + x12
F=9x3 + 27x9
Answer:
Null hypothesis:
Alternative hypothesis:
The sample size on this case is n=8, then the degrees of freedom are given by:
The statistic is given by:
For this case the value of the statistic is given
Since we are using a bilateral test the p value would be given by:
And we can use the following excel code to find it:
"=2*(1-T.DIST(2.315;7;TRUE))"
Since the p value is higher than the significance level given we FAIL to reject the null hypothesis. And the best conclusion would be:
0.05<P-value <0.10, fail to reject the null hypothesis
Step-by-step explanation:
Assuming this complete question :"Given a test statistic of t=2.315 of a left-tailed test with n=8, use a 0.05 significance level to test a claim that the mean of a given population is equal to 110.
Find the range of values for the P-value and state the initial conclusion 1 point) 0.05<P-value <0.10; reject the null hypothesis
0.05<P-value <0.10, fail to reject the null hypothesis
0.025 < P-value <0.05; reject the null hypothesis
0.025< P-value<0.05; fail to reject the null hypothesis"
For this case they want to test if the population mean is 110 or no, the systemof hypothesis are:
Null hypothesis:
Alternative hypothesis:
The sample size on this case is n=8, then the degrees of freedom are given by:
The statistic is given by:
For this case the value of the statistic is given
Since we are using a bilateral test the p value would be given by:
And we can use the following excel code to find it:
"=2*(1-T.DIST(2.315;7;TRUE))"
Since the p value is higher than the significance level given we FAIL to reject the null hypothesis. And the best conclusion would be:
0.05<P-value <0.10, fail to reject the null hypothesis
Answer:
Step-by-step explanation:
you could spilt a pie into 5 pieces and give someone 2. then you gave them 2/5 of a pie.