Answer:
(4,5)
Step-by-step explanation:
Given that M is the midpoint of the Line RS. Where the coordinates of M, R and S are
M(5,7)
R(X,Y)
S(6,9)
Here we have to find the valuer of X and Y
We will use the mid point formula which is given below.
Let put the coordinated of M and S and find coordinates of R
Hence our coordinates are
(4,5)
Domain: (-2, 0, 2, 4)
Range: (5,1, -3,7)
Range: (-5, 1, -3,7)
Range: (-5, -1,3,7)
Range: [5, 1, +3, +7)
Answer:
Range={-5,-1,3,7). [optionC]
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A. 3 imaginary; 2 real
B. 4 imaginary; 1 real
C. 0 imaginary; 5 real
D. 2 imaginary; 3 real
Answer:
B. 4 imaginary; 1 real
Step-by-step explanation:
Given the polynomial:
x^5 + 7*x^4 + 2*x^3 + 14*x^2 + x + 7
it can be reordered as follows
(x^5 + 2*x^3 + x ) + (7*x^4 + 14*x^2 + 7)
Taking greatest common factor at each parenthesis
x*(x^4 + 2*x^2 + 1) + 7*(x^4 + 2*x^2 + 1)
Taking again the greatest common factor
(x + 7)*(x^4 + 2*x^2 + 1)
Replacing x^2 = y in the second parenthesis
(x + 7)*(y^2 + 2*y + 1)
(x + 7)*(y + 1)^2
Coming back to x variable
(x + 7)*(x^2 + 1)^2
There are two options to find the roots
(x + 7) = 0
or
(x^2 + 1)^2 = 0 which is the same that (x^2 + 1) = 0
In the former case, x = -7 is the real root. In the latter, (x^2 + 1) = 0 has no real solution. Therefore, there is only 1 real root in the polynomial.
What should you do to solve the equation?
45 = x + 38
O Subtract 38 from both sides.
O Add 38 to both sides.
O Subtract 45 from both sides.
O Add 45 to both sides.
Answer:
Subtract 38 from both sides.
Step-by-step explanation:
THAT DA ANSWER
2/3(6y+9)=3/5(15x-20)
The simplified value of the exponential expression is .
Fractional power implies the root of the strength of the denominator of that integer.
For example: .
Given here the exponential expression is
So here
We know that,
Thus,
Hence the equivalent value of the given expression is 2.
Learn more about Fractional Power here -
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2
First, we are going to use the law of fractional exponents:
We can infer form our expression that and , so let's replace the values:
Notice that we can also decompose 16 into prime factors to get , so we can rewrite our expression as follows:
Finally, we can use the rule of radicals: , so: