Gary sees on a measuring cup that 200 centiliters are the same as 2 liters. how many liters are there in 300 centiliters

Answers

Answer 1

Answer: Wel, it is a ratio 200:2 so if you simplify it is 100:1. To get 300 on the left side you have to mutiply each by 3, so it turns into 300:3, so it is 3 liters. Hope this helped!

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Compute the amount of interest earned in the following simple interest problem. A deposit of $5,000 at 8.5% for 120 days = _____. $140.25
$1,402.50
$14,025
$51,000

Answers

Answer:

Option (a) is correct.

The amount of interest earned in the given simple interest problem is $140.25

Step-by-step explanation:

Given : A deposit of $5,000 at 8.5% for 120 days.

We have to calculate the amount of interest earned in the given simple interest problem.

Using Simple interest formula,

$SI=(P * r* t)/(100)$

Where SI denotes simple interest

P denotes principal

R denotes rate of interest

t denotes time period.

Thus,

Given : P = $5,000

r= 8.5%

t = 120 days

1 year = 365 days.

So , 120 days = $(120)/(365)$ year.

Substitute, we get,

$SI=(P * r* t)/(100)$

$SI=(5000 * 8.5* 120)/(100* 365)$

On simplify, we get,

SI =$ 139.72

Thus, out of given options nearest value is $140.25 (approx)

Thus, the amount of interest earned in the given simple interest problem is $140.25

I = p * r * t
I = 5000 * .085 * (1/3)
I = 140.25

A bicycle training wheel has a radius of 3 inches. The bicycle wheel has a radius of 10 inches. Approximately how much smaller, in square inches, is the areaof the training wheel than the area of the regular wheel?Use 3.14 for 흅

Answers

Answer:

$285.74\text{ inch}^2$

Step-by-step explanation:

GIVEN: A bicycle training wheel has a radius of $3\text{ inch}$ . The bicycle wheel has a radius of $10\text{ inch}$ .

TO FIND: Approximately how much smaller, in square inches, is the area of the training wheel than the area of the regular wheel.

SOLUTION:

radius of bicycle wheel $=10\text{ inch}$

area of bicycle wheel $=\pi r^2$

putting value,

area of bicycle wheel $=3.14*10^2$

$=314\text{ inch}^2$

radius of bicycle training wheel $=3\text{ inch}$

area of bicycle training wheel $=\pi r^2$

putting value,

area of bicycle wheel $=3.14*3^2$

$=28.26\text{ inch}^2$

difference in area of bicycle wheel and bicycle training wheel

$=\text{area of bicycle wheel}-\text{area of bicycle training wheel}$

$=314-28.26$

$=285.74\text{ inch}^2$

hence the training wheel is $285.74\text{ inch}^2$ smaller than regular wheel

Steven is exploring the impact of neglect on academic achievement for grade school children. He will be using a nonprobability sampling procedure, due in-part to the sensitive nature of the research topic. He begins the sampling process by selecting research participants who are the easiest to find. What type of sampling procedure is he using? a. Convenience sampling
b. Criterion sampling
c. Snowball sampling
d. Quota sampling

Answers

Answer:

A. convenience sampling

Step-by-step explanation:

The sampling procedure used by Steven is convenience sampling.

Convenience sampling is a sampling method, where samples are drawn from the closest samples available.

For example: A teacher surveying for something chooses samples from her own class. The students of her own class are the closest available samples.

What is the value of the expression below when c - 5 and d - 4 (c is to the second power)?6c2-5d+8

Answers

Well, let's write it out, shall we? 6c2-5d+8 Now plug in the numbers. 6(5^2)2-5(4)+8 Now simplify using PEMDAS Parentheses Exponents Multiplication Division Addition and Subtraction (They go together go from left to right in the equation) 5^2= 5*5 = 25 6 * 25 = 150 150 * 2 = 300 5 * 4 = 20 Rewrite the equation. 150-20+8 Use PEMDAS again ( refer to the previous mentioning) 150 - 20 = 130 130 + 8 = 138

Rachna has nickels, dimes, and quarters in her piggy bank. She has $4.65 altogether. She has three more quarters than dimes and twice as many nickels as quarters. How many quarters does Rachna have?

A. 8
B. 11
C. 22
D. 41

Answers

we can translate the given statements into algebraic expressions. In this case,

0.05x + 0.10y + 0.25z = 4.65z = 3 + yx = 2 z
solving these linear equations simultaneously, x = 22y = 8z= 11hence the answer is B. 11

For this case we have the following variables:

x: number of nickels

y: number of dimes

z: number of quarters

We now write the system of equations that models the problem:

$0.05x + 0.1y + 0.25z = 4.65 z = y + 3 x = 2z$