Which of the four regions of the Sun has the lowest temperature?
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I hope I helped! =D
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B. Calculating the angle of elevation for a building
C. A police car shining a spotlight into buildings as it drives by
D. The height of the water in Monterey Bay
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Answer:
Explanation:
It should the motion of a piston
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Answer:
Explanation:
Horizontal Launch
When an object is thrown horizontally with a speed v from a height h, it describes a curved path ruled by gravity until it eventually hits the ground.
The horizontal component of the velocity is always constant because no acceleration acts in that direction, thus:
vx=v
The vertical component of the velocity changes in time because gravity makes the object fall at increasing speed given by:
The horizontal component of the velocity is always the same:
The vertical component at t=5.5 s is:
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Answer:
True
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Radiative forcing is indeed the measure of the change in thermal energy units (watts per square meter) at the Earth's surface or in the atmosphere caused by a particular factor, such as an increase in greenhouse gases or aerosols. It quantifies the impact of various factors on the Earth's energy balance and is an important concept in climate science for understanding the drivers of climate change.
b.850 ma
c.550 ma
d.280 ma
e.650 ma
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the current approximately 7.0 ms after closing the switch is about 250 mA, which is option (a).
To find the current through the circuit 7.0 ms after the switch is closed, we can use the concept of an RL circuit. The current in an RL circuit follows an exponential growth equation, given by:
I(t) = (V/R)(1 - e^(-t/τ))
Where:
I(t) is the current at time t.
V is the voltage from the power supply (15 V in this case).
R is the resistance (60 Ω).
τ (tau) is the time constant of the circuit, given by L/R, where L is the inductance (45 mH = 0.045 H).
First, calculate the time constant τ:
τ = L/R = 0.045 H / 60 Ω = 0.00075 s.
Now, plug in the values into the equation to find I(7.0 ms):
t = 7.0 ms = 0.007 s.
I(0.007 s) = (15 V / 60 Ω) * (1 - e^(-0.007 s / 0.00075 s))
I(0.007 s) = (0.25 A) * (1 - e^(-9.333...))
Now, calculate the current:
I(0.007 s) ≈ (0.25 A) * (1 - e^(-9.333...))
I(0.007 s) ≈ (0.25 A) * (1 - 0.0000962) [Using e^(-9.333...) ≈ 0.0000962]
I(0.007 s) ≈ (0.25 A) * (0.9999038)
I(0.007 s) ≈ 0.24998 A
I(0.007 s) ≈ 250 mA
So, the current approximately 7.0 ms after closing the switch is about 250 mA, which is option (a).
Learn more about RL circuit here:
#SPJ3
Initial current = 0
Final current = (15 V) / (60 ohms) = 0.25 Ampere
Current along the way = 0.25 · (1 - e^- time / time-constant)
"time-constant" = L/R = (0.045 / 60) = 7.5 x 10⁻⁴ second
Current = 0.25 · (1 - e^-10,000t/7.5)
When t = 7 ms,
Current = 0.25 · ( 1 - e^-70/7.5)
Current = 0.25 · (1 - e^-9.33)
Current = 0.25 · (1 - 8.84 x 10⁻⁵)
Current = 0.25 · (0.9999)
Current = so close to 250 mA that you can't tell the difference.
The reason is that 7.0 mS is 9.3 time-constants, and during EVERY time-constant, the current grows by 37% of the distance it still has left to go. So after 9.3 of these, it's practically AT the target.
I have a feeling that the time in the question is SUPPOSED TO BE 7 microseconds. If that's true, then
Current = 0.25 · (1 - e^-[ 7 x 10⁻⁶ / 7.5 x 10⁻⁴ ]
Current = 0.25 · (1 - e^-0.00933)
Current = 0.25 · (1 - 0.9907)
Current = 0.25 · (0.0093)
Current = 2.32 mA ?
No, that can't be it either.
Well ! Now, I'm going to determine the true and correct final answer in the only cheap and sleazy way I have left ... by looking at all the choices offered, and eliminating the absurd ones.
The effect of an inductor in the circuit is to resist any change in current. The final current in this circuit is when it's not trying to change any more. So the final current is just the battery with a resistor across it ... (12 V) / (60 ohms). That's 0.25 Ampere, or 250 mA. The current starts at zero when the switch closes, and it builds up and builds up to 250 mA. It's never more than 250 mA.
So look at the choices ! The only one that not more than 250 mA is choice-A .
THAT has to be it. 7.0 mS is a no-brainer. It's 9.3 time-constants after the switch closes, the current has built up to 99.99% of its final value by then, it's not really trying to change much any more, the inductor is just about finished having any effect on the current, and the current is essentially at its final value of 250 mA. The action is all over.
Now, I fully realize that Mister "Rishwait" is a bot and all, and nobody really needs the answer to this question. But every cloud has a silver lining. It's a numskull question, but it earned me 10 points, and it's been a truly fascinating trip down Memory Lane.
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The overall function of the calvin cycle is to produce sugars (glucose).
CALVIN CYCLE:
- The Calvin cycle is the second stage of photosynthesis that occurs in the stoma of the chloroplast organelle.
- The Calvin cycle uses the products of the first stage called light stage (ATP and NADPH) to produce sugar molecules.
- Calvin cycle also recovers the raw materials needed for the process to continue in a cyclical manner.
- However, overall function of the calvincycle is to produce sugars(glucose).
Learn more at: brainly.com/question/3199721?referrer=searchResults
Answer:
the primary function of the Calvin cycle is to make organic products plants need, using the products from the light reactions of photosynthesis (ATP and NADPH).
Explanation:
hope this helped
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Right now the ball only has potential energy but when the ball falls that will be converted into kinetic energy because it is moving. BTW Im 14 in 9th grade ya'll should know this.
Answer:
potential; kinetic
Explanation: