What is the slope of the line through (1, 9) and (–3, 16)?

Answers

Answer 1

Answer:

For this case we have that by definition, the slope of a line is given by:

$m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}}$

Where:

$(x_ {1}, y_ {1})$ and $(x_ {2}, y_ {2})$ are two points through which the line passes.

We have as data that:

$(x_ {1}, y_ {1}) :( 1,9)\n(x_ {2}, y_ {2}): (- 3,16)$

Substituting we have:

$m = \frac {16-9} {- 3-1} = \frac {7} {- 4} = - \frac {7} {4}$

Thus, the slope of the line is $- \frac {7} {4}$

Answer:

$m = - \frac {7} {4}$

Answer 2

Answer:

Answer:

-7/4.

Step-by-step explanation:

This is the difference in the y coordinates / corresponding difference in the x coordinates.

here it is (16 - 9) / (-3-1)

= 7 / -4

= -7/4.

Solve for y:
x + 2y = 5

$x + 2y = 5\ \ \ \ |subtract\ x\ from\ both\ sides\n\n2y = 5 - x\ \ \ \ |divide\ both\ sides\ by\ 2\n\n\boxed{y =(5-x)/(2)}$

Point m is the midpoint of line ab. if the coordinates of m are 2,8) and the coordinates of a are (10,12) what are the coordinates of b

midpoint = (2, 8)

coordinate a = (10. 12)

let coordinate b = (x, y)

Find x:

0.5(10 + x) = 2

10 + x = 4

x = 4 - 10

x = -6

Find y:

0.5(12 + y) = 8

12 + y = 16

y = 16 - 12

y = 4

Answer: Coordinate b = (-6, 4)

Find the slope of the line that passes through (4,5) and (9,8)