Soup cost $10 for 3 cans. Josh spent $40 on soup. How many cans did he buy?
Answers
Answer 1
Answer:
he bought 12 cans:) because if 3 cans are 10$ and he spent 40$ just multiply 4 (the 40 dollars)times 3 (the amount of cans you get per 10 dollars).Hope this helped!
Related Questions
Choose 3 of the following that are NOT equivalent to the expression below 1/2✖️7 A.) 1✖️7➗2 B.) 1 ➖ 2✖️7 C.)1✖️7✖️2 D.)1✖️7 ➖ 2 E.) 14
Russell collected 30 stones at his grand parents' house. He decided to give his little sister 1 / 5 of the stones. How many stones did he give his sister?
How can you tell 7/10 is greater than 1/2
A grocery store so the six pack of bottled water for $3.79 a 12 pack for $6.89 which package cost The least per bottle explain your reasoning
How many 1,1/3 yards fits into 15 yards
Russell collected 30 stones at his grand parents' house. He decided to give his little sister 1 / 5 of the stones. How many stones did he give his sister?
How can you tell 7/10 is greater than 1/2
A grocery store so the six pack of bottled water for $3.79 a 12 pack for $6.89 which package cost The least per bottle explain your reasoning
How many 1,1/3 yards fits into 15 yards
Answers
Answer:
because they are and make sense
12-5xy +9x2y + 15-2y2
Answers
Just plug in x = 7 and y = -3 in place of x and y, respectively
(-3)%20%2B9(7)%5E2(-3)%20%2B%2015-2(-3)%5E2%5C%5C%5C%5C12%20-%20(-105)%20%2B%20(-1323)%20%2B%2015%20-18%5C%5C%5C%5C12%20%2B%20105%20-%201323%20%2B%2015%20-%2018%20%3D%20%5Cboxed%7B-1209%7D)
Your answer is -1209
Your answer is -1209
Answers
It should be D because the mode is the value that occurs the most often.
Answers
indentity property, anything times 1= the same number so the answer is (p) times 6
then associative property of mult
note:a(b)=a times b and =ab
a(bc)=(ab)c
so (p)6=(p6)=6p
then associative property of mult
note:a(b)=a times b and =ab
a(bc)=(ab)c
so (p)6=(p6)=6p
Answers
Steps:
1. You do 1/20 times 4 which equals 1/5 (when simplified)
2. You convert 1/5 to 2/10 which can be turned into
.2
3. You do 12.2 minus .2
4. Your answer is
12 ounces
1. You do 1/20 times 4 which equals 1/5 (when simplified)
2. You convert 1/5 to 2/10 which can be turned into
.2
3. You do 12.2 minus .2
4. Your answer is
12 ounces
y>-3x-1
justify answer
Answers
Simplify the first inequality.
Multiply 1/2 by x to get (1/2)x.
y≤(1/2)x+6 and y>−3x−1
Simplify.
y≤x/2+6 and y>−3x−1
Since x is on the right-hand side of the equation, switch the sides so it is on the left-hand side of the equation.
x/2+6≥y and y>−3x−1
Because 6 does not contain the variable to solve for, move it to the right-hand side of the inequality by subtracting 6from both sides.
x/2≥−6+y and y>−3x−1
Multiply both sides of the equation by 2.
x≥−6⋅(2)+y⋅(2) and y>−3x−1
Multiply −6 by 2 to get −12.
x≥−12+y⋅(2) and y>−3x−1
Multiply y by 2 to get y(2).
x≥−12+y(2) and y>−3x−1
Multiply y by 2 to get y⋅2.
x≥−12+y⋅2 and y>−3x−1
Move 2 to the left of the expression y⋅2.
x≥−12+2⋅y and y>−3x−1
Multiply 2 by y to get 2y.
x≥−12+2y and y>−3x−1
Reorder −12 and 2y.
x≥2y−12 and y>−3x−1
Simplify the second inequality.
Because x is on the right-hand side of the equation, switch the sides so it is on the left-hand side of the equation.
x≥2y−12 and −3x−1<y
Since −1 does not contain the variable to solve for, move it to the right-hand side of the inequality by adding 1 to both sides.
x≥2y−12 and −3x<1+y
Divide each term in the inequality by −3. When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.
x≥2y−12 and −3x/−3>1/−3+y/−3
Cancel 3 in the numerator and denominator.
x≥2y−12 and −(−1⋅x)>1/−3+y/−3
Multiply −1 by x to get −1x.
x≥2y−12 and −(−1x)>1/−3+y/−3
Rewrite −1x as −x.
x≥2y−12 and −(−x)>1/−3+y/−3
Simplify
x≥2y−12 and x>−1/3+y/−3
x≥2y−12 and x>−1/3−y/3
Point of intersection: (-2, 5)
Multiply 1/2 by x to get (1/2)x.
y≤(1/2)x+6 and y>−3x−1
Simplify.
y≤x/2+6 and y>−3x−1
Since x is on the right-hand side of the equation, switch the sides so it is on the left-hand side of the equation.
x/2+6≥y and y>−3x−1
Because 6 does not contain the variable to solve for, move it to the right-hand side of the inequality by subtracting 6from both sides.
x/2≥−6+y and y>−3x−1
Multiply both sides of the equation by 2.
x≥−6⋅(2)+y⋅(2) and y>−3x−1
Multiply −6 by 2 to get −12.
x≥−12+y⋅(2) and y>−3x−1
Multiply y by 2 to get y(2).
x≥−12+y(2) and y>−3x−1
Multiply y by 2 to get y⋅2.
x≥−12+y⋅2 and y>−3x−1
Move 2 to the left of the expression y⋅2.
x≥−12+2⋅y and y>−3x−1
Multiply 2 by y to get 2y.
x≥−12+2y and y>−3x−1
Reorder −12 and 2y.
x≥2y−12 and y>−3x−1
Simplify the second inequality.
Because x is on the right-hand side of the equation, switch the sides so it is on the left-hand side of the equation.
x≥2y−12 and −3x−1<y
Since −1 does not contain the variable to solve for, move it to the right-hand side of the inequality by adding 1 to both sides.
x≥2y−12 and −3x<1+y
Divide each term in the inequality by −3. When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.
x≥2y−12 and −3x/−3>1/−3+y/−3
Cancel 3 in the numerator and denominator.
x≥2y−12 and −(−1⋅x)>1/−3+y/−3
Multiply −1 by x to get −1x.
x≥2y−12 and −(−1x)>1/−3+y/−3
Rewrite −1x as −x.
x≥2y−12 and −(−x)>1/−3+y/−3
Simplify
x≥2y−12 and x>−1/3+y/−3
x≥2y−12 and x>−1/3−y/3
Point of intersection: (-2, 5)
Other Questions