Answer:
0.556 Watts
Explanation:
w = Weight of object = 762 N
s = Distance = 5 m
t = Time taken = 29 seconds
a = Acceleration
g = Acceleration due to gravity = 9.81 m/s²
Equation of motion
Mass of the body
Force required to move the body
Velocity of object
Power
∴ Amount of power required to move the object is 0.556 Watts
Answer:
Explanation:
effective delay = delay when no traffic x
effective delay =
Answer:
Given:
operating temperature of heat engine,
Solution:
For a reversible cycle, maximum efficiency, is given by:
Now, on re designing collector, maximum temperature, changes to
, so, the new maximum efficiency,
is given by:
Answer: 18,100
Explanation: two farms that grow wheat and corn.
Answer:
0.1 nm
Explanation:
Potential difference of the electron = 150 V
Mass of electron
Charge on electron
Plank's constant
If the velocity of the electron is v
Then according to energy conservation
According to De Broglie
B. The average velocity stays the same with distance from the entrance.
C. The maximum velocity increases with distance from the entrance.
D. The maximum velocity decreases with distance from the entrance.
E. B and C
F. B and D
Answer:
D. The maximum velocity decreases with distance from the entrance.
Explanation:
This is because over time, the pressure with with the incompressible liquid enters decreases with distance from the entrance
Answer:
C. The maximum velocity increases with distance from the entrance
Explanation:
As the fluid particles moves into the pipe, the layer of fluid in contact with the surface of the pipe come to a complete stop. This layer also causes the fluid
particles in the adjacent layers to gradually slow down as a result of friction between fluid molecules, leaving the fluid at the center of the pipe with the maximum velocity.
Since the fluid is incompressible, to make up for this velocity reduction, the velocity of the fluid at the mid-
section of the pipe has to increase to keep the mass flow rate through the
pipe constant. As a result, a velocity gradient develops along the pipe and the maximum velocity which is at the center of the pipe increases with distance from entrance.
Answer:
It is important to add presentation layer after the physical layer, so that the data along with it's headers can be translated, when the receiver machine is applying a set of different characters.
Data compression is also required to reduce the space that is occupied by data during transmission, now once the presentation is added to the physical layer, data from the physical layer can be compressed at the presentation layer and sent by improving the throughput.
Explanation:
Solution
The presentation of data involves the following as shown below:
Presentation of data comprises of the task like translating between receiver and sender devices so that machines with different capabilities sets can communicate with one another.
It involves encoding and decoding of data to provide data security that is been transmitted by different machines.
Data sometimes needs to compressed for efficiency improvement for transmission.
The physical layer of the TCP/IP protocol suite is responsible or refers to the transmission of physical data over a physical medium
It is good or important to add presentation layer after the physical layer, so that the data along with it's headers can be translated, when the receiver machine is applying a set of different characters.
Data encryption at this stage is good for security instead of encrypting the data at upper/higher layers.
Hence, it is advisable to add presentation layer after the physical layer in the TCP/IP suite.
Answer:
The layer ought to be embedded between Layer 2 and 3.
Explanation:
Applications often communicate with each other. This cannot be successful if they don't see data the same way. The Presentation Layer in the Open Systems Interconnection defines how data is presented and is often processed in the TCP/IP applications.
While the Presentation Layer does not exist as a different layer in the TCP/IP protocol order of arrangement, it is important to note that the Network Layer is also known referred to as the TCP/IP’s Network Layer.
Therefore, if the presentation of the data layer will be separated, it should be between layer 2 and 3.
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