What happens to the current as we increase the amount of stepping of our transformer? Does this help explain why the primary was warm but not the secondary? How does this result demonstrate that we can’t just use a step-up transformer to create free energy?

Answers

Answer 1
Answer:

Answer:

Current will decrease.

Explanation:

When we increase the number of stepping in transformer, the voltage will increase as its is directly proportional to the number of turn of stepping. Thus as the voltage will increase, current will decrease. As per the equation of ideal transformer,   E1 / E2 = I2 / I1

E1 and E2 are the voltages in primary and secondary winding and I1 and I2 are the current.

As the number of turns will be increased more inevitable losses will be generated that dissipates heat thus warming the primary.

Though the conservation of energy is obeyed but losses occur in this scenario hence step-up transformers cannot be used to create free energy.


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A central air-conditioner uses 3500W of electricity. If electricity costs $0.087/kW*h. calculate how much it would cost to operate the air-conditioner 24 hours a day for 4 months (120 days).

I'm taking physics and trying to figure out the 4 questions to this problem.

Answers

Answer:

Explanation:

At t = 1 velocity = 0

At t = 3 velocity = 3

slope of the line = 3-0 / 3-1 = 3/2

At t = 2

velocity = 3/2 x ( 2 - 1 )

= 1.5 m /s

velocity at t = 2 is 1.5 m /s

Position at t = 2 :

displacement at t = 2

area of graph upto  t = 2

= 1 / 2 x 1 x 1.5 = .75

position at t = 2 :

= initial position + displacement

= 10 + .75 = 10.75 m

position at 6 s :

displacement at t = 6

area of curve upto  t = 6

= 1 / 2 x 2 x 3 +  3 x 3 + 1/2 x 3 x ( 4.5 - 3 )

= 3 + 9 + 2.25

= 14.25 m

position at t = 6

= initial position + displacement

= 10 + 14.25 = 24.25 m

position at 9 s :

displacement at t = 9

area of curve upto  t = 9

= 1 / 2 x 2 x 3 +  4 x 3 + 1/2 x 4 x ( 5 - 3 )- 1/2 x 2 x 1.5

= 3 + 12 + 4 - 1.5

= 17.5  m

position at t = 9

= initial position + displacement

= 10 + 17.5 = 27.5  m

write the chemical formulae for; nitrogen monoxide, hydrochloric acid, barium phosphate, ammonium hydroxide,nitric acid​

Answers

Answer:

  • Nitrogen Monoxide = NO
  • Hydrochloric Acid = HCL
  • Barium Phosphate = (Ba)3{(Po)4}
  • Ammonium Hydroxide = (NH)4(OH)
  • Nitric Acid = H(NO)3

What storm causes flash floods?
Tornado
Thunderstorm
Hurricane

Answers

Answer:

hurricane.

Explanation:

............................

What branch of physics best explains the photoelectric effect?A.) nature of light
B.) general relativity
C.) law of conservation of momentum
D.) thermodynamics

Answers

i think its nature of light

The inner solar system contains theA)Jovian planets
B)terrestrial planets and asteroids
C)dwarf planets like Pluto

Answers

jovian planets and  dwarf planets like pluto are in the outer part of our solar system. so, terrestrial planets ,which means earth like planets, live in the inner part of our solar system. or B. is the answer

You use a 1200-watt hair dryer for 10 minutes each day. a. How many minutes do you use the hair dryer in a month? (Assume there are 30 days in the month.) b. How many hours do you use the hair dryer in a month? c. What is the power of the hair dryer in kilowatts? d. How many kilowatt-hours of electricity does the hair dryer use in a month? e. If your town charges $0.15/kWh, what is the cost to use the hair dryer for a month?

Answers

Data;

  • Power = 1200W
  • Time/day = 10 mins

Power

The is the rate of energy used to time. It is the measure of expedience of energy.

a). How many minutes is the dryer used in a month.

Assuming there 30 days in a month;

1 day = 10 mins\n30 days = x mins\nx = 30 * 10 \nx = 300 mins

This shows that the dryer is used 300 minutes in a month.

b). How many hours is the dryer used in a month.

To solve this problem, we simply need to convert the value of (a) from minutes to hours.

1hr = 60 mins\ny hr = 300 mins\ny = (300)/(60) \ny = 5 hours

The dryer was used for a total of 5 hours in a month.

c). The power of the dryer in  kilowatt.

To convert the power in watt to kilowatt, we divide by 1000.

P = 1200W\nP = (1200)/(1000) \nP = 1.2kw

The power in kilowatt is 1.2kw

d). How many kilowatt/hr of electricity used in a month.

1.2 * 5 = 6kw/h

The dryer consumes 6kw/h in a month.

e). If the town charges $0.15/kwh, the cost in a month

\$0.15 = 1hr\nx= 6hr\nx = 6 * 0.15\nx = 0.9

The cost of the dryer in a month is $0.9.

Learn more on power here;

brainly.com/question/911620

300 minuts
5 hours
1.2 killowatt
6 killowatt hour
6*0.15=0.9
$0.9