Answer:
Explanation:
Given parameters:
Concentration of H₃O⁺ = 5.6 x 10⁻²M
Solution:
To solve for the concentration of H₃O⁺ in the solution, we simply use the expression below:
pH = -log₁₀[H₃O⁺]
where [H₃O⁺] = 5.6 x 10⁻²M is the concentration of H₃O⁺
pH = -log₁₀[5.6 x 10⁻²] = - x -1.25 = 1.25
Answer:
1.25 is the pH of the given solution
Explanation:
We can determine the acidity or the basicity of the solution using the pH value.
The solution is acidic if the pH value ranges from 0 to 6.9
The solution is Basic if the pH value ranges from 7.1 to 14
The solution is neutral if the pH value is 7.
pH is defined as the negative logarithm of the Hydrogen ion concentration, that’s why the formula to find pH is given by
or
(Answer)
Please note:
When an hydrogen atom loses an electron, Hydrogen ion is formed, which will contain 1 positive proton and 0 negative electron and 0 neutral neutron.
Thus Hydrogen ion has a + charge.
Hydrogen ion is also called as a proton since it has only 1 proton in it.
Hydrogen ion in water that is,
H_3 O^+ is called as Hydronium ion.
B) steel rusting
C) paper burning
D) wood decaying
A physical change changes the state on object is in, making the answer A) iron melting. Since it's melting, it's going from solid to liquid.
Answer:
86.04 %
Explanation:
Data given:
mass of Al = 160.0 g
actual yield Al₂O₃= 260 g
Theoretical yield = ?
percent yield ofAl₂O₃ = ?
Solution:
First we have to find theoretical yield.
So,
we Look at the balanced reaction
4Al + 3O₂ -----—> 2Al₂O₃
4 mol 2 mol
As 4 mole of Al give 2 mole of Al₂O₃
Convert moles to mass
molar mass of Al = 27 g/mol
molar mass of Al₂O₃ = 2(27) + 3(16)
molar mass of Al₂O₃ = 54 + 48
molar mass of Al₂O₃ = 102 g/mol
Now
4Al + 3O₂ -----—> 2Al₂O₃
4 mol (27g/mol) 2 mol (102 g/mol)
108 g 204 g
108 grams of Al produce 204 g of Al₂O₃
So
if 108 grams of Al produce 204 g of Al₂O₃ so how many grams of Al₂O₃will be produced by 160 g of Al.
Apply Unity Formula
108 grams of Al ≅ 204 g of Al₂O₃
160 grams of Al ≅ X of Al₂O₃
Do cross multiply
mass of Al₂O₃= 204 g x 160 g / 108 g
mass of Al₂O₃ = 302.2 g
So the Theoretical yield of Al₂O₃ = 302.2 g
Now Find the percent yield of Al₂O₃
Formula Used
percent yield = actual yield /theoretical yield x 100 %
Put value in the above formula
percent yield = 260g / 302.2 g x 100 %
percent yield = 86.04 %
percent yield of Al₂O₃ = 86.04 %
the number of electrons in the atom
B.
the most common isotope of the atom
C.
the number of neutrons in the atom
D.
the atomic mass of the atom
The answer should be
A. the number of electrons in the atom