Answer and Explanation :
A man middle attack is the attack which takes place when there is a communication between the two system. This mostly happen whenever there is online communication between two systems it may be anything as email chatting etc.
It is very difficult to protect from a man middle attack but there is a technology
known as PKI technology which is used for protection from man middle attack
Answer:
See explaination
Explanation:
EndOfSentenceException.java
//Create a class EndOfSentenceException that
//extends the Exception class.
class EndOfSentenceException extends Exception
{
//Construtor.
EndOfSentenceException(String str)
{
System.out.println(str);
}
}
CommaException.java
//Create a class CommaException that extends the class
//EndOfSentenceException.
class CommaException extends EndOfSentenceException
{
//Define the constructor of CommaException.
public CommaException(String str)
{
super(str);
}
}
PunctuationException.java
//Create a class PunctuationException that extends the class
//EndOfSentenceException.
class PunctuationException extends EndOfSentenceException
{
//Constructor.
public PunctuationException(String str)
{
super(str);
}
}
Driver.java
//Include the header file.
import java.util.Scanner;
//Define the class Driver to check the sentence.
public class Driver {
//Define the function to check the sentence exceptions.
public String checkSentence(String str)
throws EndOfSentenceException
{
//Check the sentence ends with full stop,
//exclamation mark
//and question mark.
if(!(str.endsWith(".")) && !(str.endsWith("!"))
&& !(str.endsWith("?")))
{
//Check the sentence is ending with comma.
if(str.endsWith(","))
{
//Throw the CommaException.
throw new CommaException("You can't "
+ "end a sentence in a comma.");
}
//Otherwise.
else
{
//Throw PunctuationException.
throw new PunctuationException("The sentence "
+ "does not end correctly.");
}
}
//If the above conditions fails then
//return this message to the main function.
return "The sentence ends correctly.";
}
//Define the main function.
public static void main(String[] args)
{
//Create an object of Scanner
Scanner object = new Scanner(System.in);
//Prompt the user to enter the sentence.
System.out.println("Enter the sentence:");
String sentence=object.nextLine();
//Begin the try block.
try {
//Call the Driver's check function.
System.out.println(new
Driver().checkSentence(sentence));
}
//The catch block to catch the exception.
catch (EndOfSentenceException e)
{}
}
}
Answer:
Human visual behavior often includes searching, scanning, and monitoring.
While it should be possible to moderate the performance of these tasks based on the dimensions used in the table, it is often useful to analyze these situations using Signal Detection Theory (SDT).
Three suggestions for my favourite search engine that includes search are:
1. ensure that search results are graded according to the following categories using different colours:
These can help the users identify more easily the results to spend more time on. This categorisation can be done using colours. This is because of the way the eye functions. Unlike a camera snapshot, for example, the eye does not capture everything in a scene equally, but selectively picks out salient objects and features from the current context, and focuses on them so they can be processed in more detail.
2. Another suggestion is that attention needs to be paid to where people look most of the time. It is not out of place for people to instinctively avoid search results that have dollar signs or currency signs especially when they are not searching for a commercial item.
3. Lastly in displaying results that have images, it best to use sharp images. The theory suggests with respect to contrast, clarity and brightness that sharper and more distinct objects appear to be nearer, and duller objects appear to be farther away. To elicit the interest of the reader, targeted results or information from search engines must make use of the factors of contrast, clarity and brightness.
Cheers!
Answer:
CER
Explanation:
The CER refers to equanimity between an identification technology's False Acceptance Rate and its False Rejection Rate, which is “the best summary measure of face recognition technologies' efficacy,” according to a statement from Applied Recognition.
[8:53 PM]
2) Create a button with label “true” , clicking on the button toggle the value from “true” => “false” and “false” => “true”.(edited)
techsith (patel) — 03/03/2021
3) Create a counter and a button. clicking on the button increments the counter by one. double clicking on the button resets the counter to 0
Answer:too many words ahhh
Explanation:
(assuming jsx)
function Buttons (props) {
return(
{props.counterValue}
counter
increment
reset
);
}
var counterValue = 1;
function addup(a){
if(counterValue + a <= 20){
counterValue += a;
} else if (counterValue + a > 20){
//do nothing
}
ReactDOM.render(
,
document.getElementById('root')
);
}
function reset() {
counterValue = 1;
ReactDOM.render(
,
document.getElementById('root')
);
}
Answer:
Written in C++
#include<iostream>
using namespace std;
int main()
{
int N;
cout<<"Length of Array: ";
cin>>N;
int A[N], B[N];
for(int i =0;i<N;i++) {
cin>>A[i];
}
for(int i =0;i<N;i++) {
B[i] = A[i];
}
for(int i =0;i<N;i++) {
cout<<B[i]<<" ";
}
return 0;
}
Explanation:
This line declares the length of the Array; N
int N;
This line prompts user for length of array
cout<<"Length of Array: ";
This line gets user input for length of array
cin>>N;
This line declares array A and B
int A[N], B[N];
The following iteration gets input for Array A
for(int i =0;i<N;i++) {
cin>>A[i];
}
The following iteration gets copies element of Array A to Array B
for(int i =0;i<N;i++) {
B[i] = A[i];
}
The following iteration prints elements of Array B
for(int i =0;i<N;i++) {
cout<<B[i]<<" ";
}