Answer:
$0.21
Step-by-step explanation:
Let x be the amount of money earned per hour before raise and y be amount of money earned per hour after raise.
We have been given that before raise he worked 38 hours and earned $220. We can represent this information as:
We are also told that the next week, he received a raise. After raise he worked 30 hours and made $180. We can represent this information as: .
Let us solve for x and y.
Therefore, before raise Mike earned $5.7894 per hour.
Therefore, after raise Mike earned $6 per hour.
Now let us subtract 5.7894 from 6 to find Mike's raise.
Therefore, amount of Mike's raise to the nearest cent is $0.21.
Let x be the rate of speed of slower cyclist
and x+10 = rate of speed of faster cyclist
Distance = Speed * Time
5x + 5(x+10) = 200
5x + 5x + 50 = 200
10x = 200-50
10x = 150
x = 15
Rate of speed of slower cyclist: 15 mph
Rate of speed of faster cyclist = 15+10 => 25 mph
In this problem, the speed of the faster cyclist is 25 mi/h and the speed of the slower cyclist is 15 mi/h. We determine this by setting up and solving an algebraic equation considering the total distance and time they traveled.
This problem is a typical example of relativerate and distance problems in algebra. First, define the speed of the faster cyclist as x m/h. Then, the speed of the slower cyclist is x-10 m/h. They travel towards each other, so their rates add up. That's why the equation becomes x+(x-10) = 200/5. We get this equation because the total distance they traveled is 200 miles (meeting in the middle), and they traveled for 5 hours.
Solving the equation x+(x-10) = 40 gives 2x-10 = 40, then 2x = 50, and finally x = 25. So, the faster cyclist is moving at 25 mi/h, and the slower cyclist is moving at 15 mi/h (25-10).
#SPJ2
it would be 9.87 good luck