What is the area of the figure? A. 90 mm2 B. 110 mm2 C. 130 mm2 D. 180 mm
Answers
Answer 1
Answer:
I see two shapes in the given figure. A rectangle and a triangle.
We need to get the area of the rectangle and triangle. We then deduct the area of the triangle from the area of the rectangle to get the area of the shaded portion.
Area of the rectangle = length * width
A = 11 mm * 10 mm
A = 110 mm²
Area of the triangle = (hb)/2
A = [(11mm-7mm)(10mm)] ÷ 2
A = (4mm*10mm) / 2
A = 40mm²/2
A = 20mm²
110 mm² - 20mm² = 90 mm² Choice A.
We need to get the area of the rectangle and triangle. We then deduct the area of the triangle from the area of the rectangle to get the area of the shaded portion.
Area of the rectangle = length * width
A = 11 mm * 10 mm
A = 110 mm²
Area of the triangle = (hb)/2
A = [(11mm-7mm)(10mm)] ÷ 2
A = (4mm*10mm) / 2
A = 40mm²/2
A = 20mm²
110 mm² - 20mm² = 90 mm² Choice A.
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16 times
hope this helps
hope this helps
you can arrange them 16 time
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Step-by-step explanation:
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Answers
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The square root of 80 p to the 3rd
Answers
√(80 p³ = √ (16 x 5 x p² x p)
You know the square roots of 16 and p , so you can take them out of the radical.
= (4p) x √(5p)
You know the square roots of 16 and p , so you can take them out of the radical.
= (4p) x √(5p)
I added pictures, but I don't know how they'll come out when I post this. Sorry if it ends up looking weird :/
You should start by factoring the number inside the cube root/radical sign, which in this case is 80. If you remember how to do factor trees, just do that with the number 80. The p is already prime, so you don't need to worry about it at first. (see picture 1)
Now see if there are any triplets of prime numbers. In this case, there is a triplet of twos (see picture 2), so you bring down one 2 to your answer (see picture 3). If there had been two triplets, you would have brought both numbers down and multiplied them.
There should be three prime numbers left: 2, 5, and p. (see picture 4) Go back down to your answer, put a cube root/radical sign next to the 2, and put your prime numbers in the cube root/radical. You should have 2∛2·5p. 2·5 can be simplified to 10, so your final answer will be 2∛10p (see picture 5).
You should start by factoring the number inside the cube root/radical sign, which in this case is 80. If you remember how to do factor trees, just do that with the number 80. The p is already prime, so you don't need to worry about it at first. (see picture 1)
Now see if there are any triplets of prime numbers. In this case, there is a triplet of twos (see picture 2), so you bring down one 2 to your answer (see picture 3). If there had been two triplets, you would have brought both numbers down and multiplied them.
There should be three prime numbers left: 2, 5, and p. (see picture 4) Go back down to your answer, put a cube root/radical sign next to the 2, and put your prime numbers in the cube root/radical. You should have 2∛2·5p. 2·5 can be simplified to 10, so your final answer will be 2∛10p (see picture 5).
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