MATHEMATICS HIGH SCHOOL

Darcie wants to crochet a minimum of 3 blankets to donate to a homeless shelter. Darcie crochets at a rate of 1/15, end of a blanket per day. She has 60 days until when she wants to donate the blankets, but she also wants to skip crocheting some days so she can volunteer in other ways.Write an inequality to determine the number of days, Darcie can skip crocheting and still meet her goal.

Answers

Answer 1
Answer:

Answer:

x≤ 60 - (3÷1/15)

Step-by-step explanation:

Number of blankets to be made = 3

Darcie crochets 1/15 blanket per day

To crochet one carpet she needs = 15 days

To crochet three carpets she needs = 15*3 = 45 days

Number of days she had = 60 days

She can skip days = 60-45 = 15 days

Let x be the number of days to complete her work.

Thus the equation becomes x≤ 60 - (3÷1/15)

You can solve for x to determine the number of days, Darcie can skip crocheting, you will get the answer 15....

Related Questions

The graph shows two lines, A and B:A graph is shown with x- and y-axes labeled from 0 to 6 at increments of 1. A straight line labeled A joins the ordered pair 3, 0 and the ordered pair 0, 6. Another straight line labeled B joins the ordered pair 0, 0 and the ordered pair 5, 5. Based on the graph, which statement is correct about the solution to the system of equations for lines A and B? A (0, 6) is the solution to both lines A and B. B(0, 6) is the solution to line B but not to line C(2, 2) is the solution to both lines A and B. D (2, 2) is the solution to line A but not to line
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If the angles of a triangle are in ratio 2:3:7 find the measure of all the angles of the triangle
A customers services representative earns $13 an hour and he works 24 hours a week . What is his weekly wage
a circular fountain has a radius of 9.4 ft find its circumstance to the nearest hundredth using pi over3

Can anybody help by forming and solving this equation (plz Show steps and worhing)A train has 180 passengers At the fist stop X get off and 24 get on At the second stop half get off and 40 get on There are now 134 passengers How many passengers got off at the 1st stop (X)

thks 4 any help

Answers

so a the start 180 passengers are on the train
at the first stop x get off and 24 get on or
180-x+24=204-x

at the second stop half get off and 40 get on or
204-x-([204-x]/2)+40 or
204-x-102+x/2+40
104-1/2x+40
144-1/2x
there are now 134 passengers
144-1/2x=134
subtract 134 from both sides
10-1/2x=0
add 1/2x to both sides
10=1/2x
mutliply both sides by 2/1 to make 1/2x=1/1x
20=x
20 got off at the first stop
Form an equation using information given
180 - x - 24 + 40 = 134
then simplify and solve
196 - x = 134
196 - 134 = x
62 = x
therefore 62 people got off at the first stop

Evaluate the following y^2-5y+2

Answers

If y = 3, then you substitute 3 into wherever it says y.

So the original: 
y² - 5y + 2

becomes:
3² - 5×3 + 2.

which is:
9 - 15 + 2.

9 - 15 = -6
-6 + 2 = -4.

-4 is the answer.

Simplify and solve this equation for q: 3q + 5 + 2q – 5 = 65. A. q = 23
B. q = 13
C. q = 15
D. q = 11

Answers

 3(13) + 5 + 2(13) – 5 = 65Answer is B
3q + 5 + 2q - 5 = 655q + 0 = 655q divided by 65 is 13 .Answer is B .

What are the zeros of the polynomial function: f(x) = x3 + x2 – 6x ? ...?

Answers

The solution to the problem is as follows:

　 
x³ + x² − 6x = 0 
x (x² + x − 6) = 0 
x (x − 2) (x + 3) = 0 
x = 0, 2, −3 


f(x) = 2x³ + 5x² + 6x − 4 
f(−x) = −2x³ + 5x² − 6x − 4 

Let's look at signs only and how many sign changes there are: 
f(x) = + + + − 
1 sign change ----> 1 positive root 
f(−x) = − + − − 
2 sign changes ----> 2 or 0 negative roots 

Min. number of real roots = 1 ----> max. number of complex roots = 2 
Max. number of real roots = 3 ----> min. number of complex roots = 0

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Simplify (3n – 2m)2 = ? a. 6n2 – 12mn – 4m2 b. 9n2 – 12mn – 4m2 c. 9n2 12mn 4m2 d. 9n2 – 12mn 4m2

Answers

If you would like to simplify (3n - 2m)^2, you can do this using the following steps:

(3n - 2m)^2 = 3^2 * n^2 - 3 * 2 * 2 * n * m + 2^2 * m^2 = 9n^2 - 12nm + 4m^2

The correct result would be d. 9n^2 - 12nm + 4m^2. 

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Answers

The answer is 4000 because in sig fig, you don't count the zeros after the number unless there is a decimal after 0.
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