Answer:
During high fever a wet cloth is kept on the forehead of a person to decrease the temperature of body. ... When the wet cloth is placed on the forehead, water in wet cloth starts to evaporate and it starts to absorb a lot of heat from our body. Hence it is used to decrease the temperature of body.
To find the planet's radius in terms of the radius Rg of Earth, use the equation g = GM/R^2 and substitute 2g for g. Solve for R to get R = sqrt(1/(2gMg)) * Rg.
To find the planet's radius in terms of the radius Rg of Earth, we need to understand the relationship between the gravitational field and the mass and radius of a planet. The magnitude of the gravitational field on the surface of a planet is given by g = GM/R2, where G is the gravitational constant, M is the mass of the planet, and R is its radius. For the planet in question, we are told that the magnitude of the gravitational field is 2g and its mass is half the mass of Earth. Since the gravitational field is 2g, we can substitute g with 2g in the equation and solve for R in terms of Rg:
2g = GM/R2 → 2gR2 = GM → 2gR2 = (GMg)/(2Rg) → R2/Rg = 1/(2gMg) → R = sqrt(1/(2gMg)) * Rg
#SPJ12
To find the radius of a planet with a gravitational field twice that of Earth's and half the mass, the radius is calculated to be half of Earth's radius.
The magnitude of the gravitational field strength g on a planet is given by the equation g = G(M/R^2), where G is the universal gravitation constant, M is the planet's mass, and R is the planet's radius. Given that the gravitational field on the surface of the particular planet is 2g where g is Earth's gravitational field, and the planet's mass is half of Earth's mass, we can derive the planet's radius in terms of Earth's radius Rg. Setting up the proportion (G(1/2M_Earth)/(R^2)) / (G(M_Earth)/(Rg^2)) = 2, and simplifying, we find that R^2 = (1/4)Rg^2. Taking the square root of both sides gives us the final relation R = (1/2)Rg.
#SPJ3
Answer:
resistances in parallel combination of resistance.
1/Rp = 1/R1 + 1/R2 + 1/R3....
The potential difference will be V.
By applying Ohm's law,
V = IR
A. you're able to pull through facing out
B. you're able to park farther away from the building
C. you're able to reverse out of the parking spot
D. they are located in a parking garage
Option (A) is correct
Straight-in spaces can leave you a safer out if you're able to pull through facing out
Straight-in parking is a method to park a vehicle where the vehicle is guided and parked safely in between the guiding lines.
Each car is provided a separate slot for parking. It thus helps to prevent blockage of cars. Each car can move in and out freely without any congestion.
Straight-in parking is the most traditional approach of parking which saves time for drivers, allows for two-way traffic as well.
The driver can line up from multiple angles. But the safest way to leave out the Straight-in parking is to pull through facing out.
So option A is the most suitable option in the provided case.
Learn more about straight-in parking:
Answer: A. You're able to pull through facing out
Explanation: DriversED
B. There will be a decrease in the population of snakes in the ecosystem.
C. The nutrition of the soil in the ecosystem will decrease.
D. More type of plants will begin growing in the ecosystem.