Carbonyl fluoride, COF2, is an important intermediate used in the production of fluorine-containing compounds. For instance, it is used to make the refrigerant carbon tetrafluoride, CF4 via the reaction 2COF2(g)⇌CO2(g)+CF4(g), Kc=4.90 If only COF2 is present initially at a concentration of 2.00 M, what concentration of COF2 remains at equilibrium?

Answers

Answer 1
Answer:

Answer : The concentration of COF_2 remains at equilibrium will be, 0.37 M

Explanation :  Given,

Equilibrium constant = 4.90

Initial concentration of COF_2 = 2.00 M

The balanced equilibrium reaction is,

                       2COF_2(g)\rightleftharpoons CO_2(g)+CF_4(g)

Initial conc.    2 M                 0             0

At eqm.         (2-2x) M          x M         x M

The expression of equilibrium constant for the reaction will be:

K_c=([CO_2][CF_4])/([COF_2]^2)

Now put all the values in this expression, we get :

4.90=((x)* (x))/((2-2x)^2)

By solving the term 'x' by quadratic equation, we get two value of 'x'.

x=1.291M\text{ and }0.815M

Now put the values of 'x' in concentration of COF_2 remains at equilibrium.

Concentration of COF_2 remains at equilibrium = (2-2x)M=[2-2(1.219)]M=-0.582M

Concentration of COF_2 remains at equilibrium = (2-2x)M=[2-2(0.815)]M=0.37M

From this we conclude that, the amount of substance can not be negative at equilibrium. So, the value of 'x' which is equal to 1.291 M is not considered.

Therefore, the concentration of COF_2 remains at equilibrium will be, 0.37 M


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Answers

At chemical equilibrium,the forward and backward reactions are equal and opposite.

What is chemical equilibrium?

Chemical equilibrium is defined as the condition which arises during the course of a reversible chemical reaction with no net change in amount of reactants and products.A reversible chemical reaction is the one wherein the products as soon as they are formed react together to produce back the reactants.

At equilibrium, the two opposing reactions which take place take place at equal rates and there is no net change in amount of the substances which are involved in the chemical reaction.At equilibrium, the reaction is considered to be complete . Conditions which are required for equilibrium are given by quantitative formulation.

Factors which affect chemical equilibrium are change in concentration , change in pressure and temperature and presence of catalyst.

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The voltage generated by the zinc concentration cell described by, zn(s)|zn2 (aq, 0.100 m)||zn2 (aq, ? m)|zn(s),is 16.0 mv at 25 °c. calculate the concentration of the zn2 (aq) ion at the cathode.

Answers

The concentration cell is:
Zn(s) \ Zn²⁺(aq,0.100 M) // Zn²⁺(aq, x M) \ Zn(s)
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Answers

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Answers

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Answers

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Answers

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