Answer:
1.4959787 × 10^8
Step-by-step explanation:
Calculating scientific notation for a positive integer is simple, as it always follows this notation: a x 10^b.
Follow the steps below to see how 149,597,870 is written in scientific notation.
Step 1
To find a, take the number and move a decimal place to the right one position.
Original Number: 149,597,870
New Number: 1.49597870
Step 2
Now, to find b, count how many places to the right of the decimal.
New Number: 1 . 4 9 5 9 7 8 7 0
Decimal Count: 1 2 3 4 5 6 7 8
There are 8 places to the right of the decimal place.
Step 3
Building upon what we know above, we can now reconstruct the number into scientific notation.
Remember, the notation is: a x 10^b
a = 1.4959787 (Please notice any zeroes on the end have been removed)
b = 8
Now the whole thing:
1.4959787 x 10^8
Step 4
Check your work:
10^8 = 100,000,000 x 1.4959787 = 149,597,870
Hope this helped.
integer to represent the total temperature change.
Answer:
I think the integer that represents the change in temperature is -15.
The expression representing the temperature change is 3 * -3, and the total temperature change, calculated from this, is -9 degrees.
In this problem, we are given that the temperature dropped 3 degrees every hour for a total of 3 hours. To find the total temperature change, we must multiply the number of hours by the change in temperature every hour. So, the expression to represent this situation is 3 * -3.
To find the total temperature change, we plug in the given numbers into the expression. This results in -9. The negative sign indicates a drop in temperature. So, the integer representing the total temperature change is -9 degrees.
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There are two zeros of the function g(x) that is 11 , -11
The zero of a function is any replacement for the variable that will produce an answer of zero. Graphically, the real zero of a function is where the graph of the function crosses the x‐axis; that is, the real zero of a function is the x‐intercept(s) of the graph of the function.
According to the question
g(x) = - 484
To find the zeros of a function, find the values of x where g(x) = 0.
Therefore,
0 = - 484
0 =
0=
i.e ,
Hence , there are 2 zeros of the function g(x) that is 11 , -11 .
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Answer:
Step-by-step explanation:
A.54
B.18
C.36
D.27
Answer:
B. 18
Step-by-step explanation:
Base: 3-(-6)=9
Height: 6-2=4
Area =1/2bh = 1/2(9)(4)= 18 square units
Richard's gross pay for the month was $ 4,512.5.
It is required to find the gross pay for the month.
Arithmetic is the branch of mathematics that deals with the study of numbers using various operations on them. Basic operations of math are addition, subtraction, multiplication and division. These operations are denoted by the given symbols.
Given:
commission rate: 3.00% for oil changes, 5.00% for tune ups and 6.25% on auto part sales.
salary = $2,450.00 per month
Last month salary= $2,500.00 in oil changes,
tune ups=$4,500.00
sold =$28,200.00 in parts.
According to given question we have,
2,450 + (2,500 x 0.03) + (4,500 x 0.05) + (28,200 x 0.0625) = X
2,450 + 75 + 225 + 1,762.5 = X
2,450 + 2,062.5 = X
4,512.5 = X
Therefore, Richard's gross pay for the month was $ 4,512.5.
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Answer:
21
Step-by-step explanation:
2. 3/5 f
3. 2/5 f
4. 3/5 + f
The correct expression for the frequency of the lower note when two musical notes are a sixth apart is: 3/5 f
Given that two musical notes are a “sixth” apart, the frequency of the lower note is 3/5 the frequency of the higher note.
We need to determine the expression for the frequency of the lower note.
When two musical notes are a "sixth" apart, it means that there are five whole steps or intervals between the two notes.
In music theory, each whole step corresponds to multiplying the frequency by a constant factor.
If we denote the frequency of the higher note as f, then the frequency of the lower note, which is 3/5 times the frequency of the higher note, can be calculated by multiplying f by 3/5.
Therefore, the correct expression for the frequency of the lower note is 3/5 f.
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Answer:
2. 3/5 f
Step-by-step explanation:
the lower note is the product of it's fractional part and the frequency of the higher note.