Find the result when 20 is increased by 95%.

Answers

Answer 1

Answer: 10 percent is 2 and 5 percent is 1. 2 times 9 is 18. That is 90 percent. 18 plus 1 is 19 which is 95 percent. 20 plus 19 is 39 so the answer is 39.

Answer 2

Answer:

Final answer:

To find the result when 20 is increased by 95%, you will need to calculate 95% of 20, which is 19, and then add it to 20. The result is 39.

Explanation:

To find the result when 20 is increased by 95%, you will need to calculate 95% of 20 and add it to 20. Here's how:

Calculate 95% of 20: 0.95 * 20 = 19
Add 19 to 20: 20 + 19 = 39

So, the result when 20 is increased by 95% is 39.

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Step-by-step explanation:

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A new car sells for $25,000. The value of the car decreases by 15% each year. What is the approximate value of the car 5 years after it is purchased?

Answers

The answer is $11,092.63.

This could be calculated using the proportion. If the value of the car decreases by 15% each year, that means that after each year the value of the car is 85% of the value from the first year.

After 1st year:
$25,000 : 100% = x1 : 85%
x1 = $25,000 · 85% ÷ 100%
x1 = $21,250

After 2nd year:
$21,250 : 100% = x2 : 85%
x2 = $21,250 · 85% ÷ 100%
x2 = $18,062.5

After 3rd year:
$18,062.5 : 100% = x3 : 85%
x3 = $18,062.5 · 85% ÷ 100%
x3 = $15,353.12

After 4th year:
$15,353.12 : 100% = x4 : 85%
x4 = $15,353.12 · 85% ÷ 100%
x4 = $13,050.15

After 5th year:
$13,050.15 : 100% = x5 : 85%
x5 = $13,050.15 · 85% ÷ 100%
x5 = $11,092.63

Therefore, the value of the car 5 years after it is purchased is $11,092.63.

Answer:

Option A on edg

Step-by-step explanation:

Point A, located at (-5, 0), is rotated 90°. What are the coordinates of point A'?

Answers

Answer:

(0 -5)

i hope this helps

How do you factor 80y^2-4y-4? or is it prime?

Answers

$80y^2-4y-4\n\na=80;\ b=-4;\ c=-4\n\n\Delta=b^2-4ac\n\n\Delta=(-4)^2-4\cdot80\cdot(-4)=16+1280=1296 > 0\n\ny_1=(-b-\sqrt\Delta)/(2a);\ y_2=(-b+\sqrt\Delta)/(2a)\n\n\sqrt\Delta=√(1296)=36\n\ny_1=(4-36)/(2\cdot80)=(-32)/(160)=-(1)/(5);\ y_2=(4+36)/(2\cdot80)=(40)/(160)=(1)/(4)$

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$80y^2-4y-4=4(20y^2-5y+4y-1)=4[5y(4y-1)-(4y-1)]=\n \n=4(4y-1)(5y-1)$

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