Answer:
50
Step-by-step explanation:
m<1+m<2+m<3 = 180 this forms a straight line
m<2 = 90 degrees
m<1 + 90 + m<3 = 180
Subtract 90 from each side
m<1 + 90-90 + m<3 = 180-90
m<1 + m<3 = 90
70 +m<1+m<2 = 180 this forms a straight line
70 + m<1 + 90 = 180
Combine like terms
160 + m<1 = 180
Subtract 160 from each side
160-160 + m<1 = 180-160
m<1 = 20
m<1 + m<3 = 90
20 + m<3 = 90
Subtract 20 from each side
20-20 +m<3=90=20
m<3 = 70
We want to find m<3 - m<1
m<3 - m<1
70 -20
50
B. –6 ≤ x < –2
C. –2 ≤ x < 4
D. 0 ≤ x < 6
The width of the rectangle with an area x² = 19x + 12 is (4x + 3).
The area of a rectangle is the product of its length and width.
The perimeter of a rectangle is the sum of the lengths of all the sides.
We know the area of a rectangle is (length×widh).
Given, A rectangle has an area of 4x² + 19x + 12 and a length of (x + 4).
∴ width of the rectangle is = (4x² + 19x + 12)/(x + 4).
Or, we know that the product of two linear equations is a quadratic so,
4x² + 19x + 12.
4x² + 16x + 3x + 12.
4x(x + 4) + 3(x + 4).
(x + 4)(4x + 3).
So, the width of the rectangle is (4x + 3).
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Answer: 7.19
Step-by-step explanation:
Math
How loud is the jetski when the person is 45 feet away?
Answer
7.2593 decibels
Explanation
L ∝ 1/d² Inserting the constant of variation,
L = k/d²
k = Ld²
= 75 × 14²
= 14,700
When d = 45 feet;
L = 14,700/45²
= 14,700/2,025
= 7.2593 decibels
When the person is 45 feet away from the jetski, it is approximately 24.07 decibels loud.
We can use the inverse square law to find how loud the jetski is when the person is 45 feet away. The inverse square law states that the loudness (\(L\)) is inversely proportional to the square of the distance (\(d\)):
We are given that when the person is 14 feet away,. We can use this information to find the value of \(k\):
Now, solve for \(k\):
Now that we have the value of \(k\), we can use it to find the loudness (\(L\)) when the person is 45 feet away:
Plug in the value of \(k\) we found:
Calculate this expression to find the loudness (\(L\)) when the person is 45 feet away:
So, when the person is 45 feet away from the jetski, it is approximately 24.07 decibels loud.
Learn more about inverse square law at brainly.com/question/30562749
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