Consider the following pair of equations:x + y = –2
y = 2x + 10

If the two equations are graphed, at what point do the lines representing the two equations intersect?


(–4, 2)
(4, 2)
(–2, 4)
(2, 4)

Answers

Answer 1
Answer: Asking the Math Gods...


x=-4
y=2

Answer 2
Answer: The 2 lines will cross at what is called the "point of intersection" It is the (x, y) coordinates that are the same for line one and line two.  Since the coordinates are equal, we can set them equal to one another in the equations and solve for the value... Let me show you...

We set the y coordinates equal to one another first.  Since they give us one of the y coordinates as y = 2x + 10, we use it in the other equation so we can solve for the x coordinate...

x + y = -2

Since y = 2x + 10 then

x + 2x + 10 = -2
3x + 10 = -2
3x = -12
x = -12/3 = -4

Now that we have a value for the x coordinate, we can substitute it back into one of the equations to solve for the y coordinate...

x + y = -2
-4 + y = -2
y = -2 + 4
y = 2

So you now have the x and y coordinates that are the same for each equation, so that is the point of intersection...

(-4, 2)

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If 3a - 2 = 10, what is the value of 8a + 1?

Answers

Answer:

8a+1=33

Step-by-step explanation:

you can solve 3a-2=10 by simplifying to 3a=12, so a=4. Then you replace the a in 8a+1 with 4 to get 32+1, which is 33

Answer:

33

Step-by-step explanation:

3a-2= 10

3a=12

a=4

in this equation a=4 so you substitute that value into the other equation

8(4) +1=33

Given the parent functions f(x) = 3x + 2 and g(x) = 5x − 10, what is g(x) − f(x)?

Answers

Hello,

g(x)-f(x)=5x-10-(3x+2)=2x-12
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28.5 g of iron shot is added to a graduated cylinder containing 45.50 mL of water. the water level rises to the 49.10 mL mark. From this information, calculate the density of iron.

Answers

7.92 g/cm³ is the density of the iron sheet.

Density is calculated by the formula:

= Mass / Volume

The mass here is 28.5 g

The Volume is:

= Volume of water after iron shot added - Volume before shot added

= 49.10 - 45.50

= 3.6 mL

The units for density is g / cm³ so you need to convert the mL to cm³.

1 cm³ = 1 mL

3.6 mL is therefore 3.6 cm³.

Density is:

= 28.5 / 3.6

= 7.92 g / cm³

In conclusion, the density of the iron shot is 7.92 g /cm³.

Find out more at brainly.com/question/8287765.

Density=mass/volume.
1) we have to calculate the iron volume in liters.
iron volume=second level - first level=49.10 ml-45.50 ml=3.6 ml
3.6 ml=3.6 ml(1 liter / 1000 ml)=0.0036 liters 

2) we calculate the mass iron in kg.
28.5 g=28.5 g(1 kg /1000 g)=0.0285 kg.
2) we calculate the density of iron.
density=0.0285 kg / 0.0036 liters=7.92 kg/L

7.92 kg/l=7.92 kg/L(1000 g/1Kg)(1000 cm³/1 L)=7.92 g/cm³.

answer: From this information the Iron density is 7.92 Kg/L or  7.92 g/cm³.

If k is non zero digit for which base of k is the sum, 1+kk=100 true?

Answers

no, i don't think it's true

For a project in her Geometry class, Chee uses a mirror on the ground to measure theheight of her school's football goalpost. She walks a distance of 14.35 meters from the
goalpost, then places a mirror on flat on the ground, marked with an X at the center.
She then steps 1.4 meters to the other side of the mirror, until she can see the top of
the goalpost clearly marked in the X. Her partner measures the distance from her
eyes to the ground to be 1.65 meters. How tall is the goalpost? Round your answer to
the nearest hundredth of a meter.

Answers

The geometry technique that Chee uses to find the height of the goalpost is the equal ratio of the corresponding sides of similar triangles.

Correct response:

  • The eight of the goalpost is approximately 16.91 meters.

Methods used to calculate the height

The length Chee is using the mirror to measure = The height of her school's football goalpost

The distance of the mirror from the goalpost = 14.35 meters

The distance on the other side of the mirror Chee steps to =  1.4 meters

The distance from her eyes to the ground =1.65 meters

Required:

How tall is the goalpost.

Solution:

By using similar triangles relationships, we have;

(1.65)/(1.4) = \mathbf{(Height \ of \ the \ goalpost, h)/(14.35) }

Which gives;

h = (1.65)/(1.4) * 14.35 = 16.9125 \approx \mathbf{ 16.91}

  • The height of the goalpost, h ≈ 16.91 meters

Learn more about similar triangles here:

brainly.com/question/10676220

The dimensions of a large room are double the dimensions of a small room.Both rooms are rectangular prisms. The volume of the small room is 10 cubic
metres.
What is the volume of the large room?

Answers

The volume would be 80 cubic metres. Think about the three different dimensions for the small room as x,y and z. Therefore the volume is x*y*z= xyz. Now for the bigger room, the dimensions would be 2x,2y and 2z. Therefore, its volume would be 2x*2y*2z= 8xyz. Since xyz (volume of the smaller room)= 10 cubic metres, the bigger room's volume will be 8*10= 80 cubic metres.