MATHEMATICS HIGH SCHOOL

What is the surface area of a rectangular prism with a base length of 9 yd, a base width of 7 yd, and a height of 4 yd? A.504 yd2


B.127 yd2


C.254 yd2


D.252 yd2

Answers

Answer 1
Answer: Asking the Math Gods...

The answer is C.

2(WL+HL+HW)
Answer 2
Answer:

Answer:

c. 254 yd2

Step-by-step explanation:

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PLZ HELP, ASAP! A hotel offers two activity pages. One costs $192 and includes 3 hours of horseback riding and 2 hours of paasailing. The second costs $213 and includes 2 hours of horsebac riding and 3 hours of parasailing. What is the cost for 1 hour of each activity?
A. Parasailing: $39; Horseback Riding: $48
B. Parasailing: $51; Horseback Riding: $30
C. Parasailing: $27; Horseback Riding: $46
D. Parasailing: $63; Horseback Riding: $24

Answers

Greetings!

Answer:

Horseback riding costs $30 and parasailing costs $51, so B.

Step-by-step explanation:

This is answered by using simultaneous equations, let x be parasailing and y be horseback riding.

3y + 2x = 192

2y + 3x = 213

Multiply each equation by the number in front of the y of the other equation:

2 x (3y + 2x = 192)

3 x (2y + 3x = 213)

Which results in:

6y + 4x = 384

6y + 9x = 639

Simply minus the two equations to get rid of the y:

6y - 6y = 0

4x - 9x = -5x

384 - 639 = -255

The negatives cancel out which give a result:

5x = 255

x = (255)/(5)

x = 51

So parasailing costs $51

Now you can simply plug this value into one of the equations:

3y + (2 x 51) = 192

192 - 102 = 3y

90 = 3y

y = (90)/(3)

y = 30

So horseback riding costs $30!


Hope this helps.

Graph the line for this problem:    y=3x+6

Answers

y=3x+6\n\nfor\ x=0\to y=3\cdot0+6=6\to A(0;\ 6)\n\nfor\ x=-2\to y=3\cdot(-2)+6=-6+6=0\to B(-2;\ 0)
y=3x+6 \n \nx=0 \n \ny=3*0+6\n \ny=6 \n \nA(0,6)


y=0 \n \n0=3x+6\n \n3x=-6/:3\n \nx=-2 \n \nB(-2,0)

The number line is a graph of the _____. A)real numbers. B)integers. C)rational numbers

Answers

The number line is a graph of the A)real numbers. Because number line includes rational and irrational numbers.

At Southwest HS, the number of student in band is 1 3/4 times the number in orchestra. If 56 students are in orchestra, how many are in band?

Answers

It is important to take note of all the information's that are given in the question. It would be easy to solve the problem based on the information's given in the question.
Number of students in orchestra = 56
The number of students in band is = 1 3/4 times that are in orchestra
Then
Total number of students in band = (7/4) * 56
                                                     = 7 * 14
                                                     = 98
So 98 students are there playing in the band. I hope the answer and the procedure is clear to you. In future you can use this procedure to solve similar kind of problems without requiring any help from outside.
56 students* (1 3/4)= 98 students.

There are 98 students in the band~

50% of all the cakes Lucy bakes that week were party cakes: one fifth were fruit cakes and the remainder were sponge cakes. What percentage of cakes were sponge cakes ?

Answers

50% is equal to 5/10 so 5/10 were party cakes 1/5x2=2/10 so 2/10 were fruit cakes 5/10+2/10=7/10 so 10/10 which is 100% of all cakes 10/10-7/10=3/10 so 3/10 of the cakes were sponge cakes.

What is x+y=3 2x+4y=8

Answers

x + y = 3
2x + 4y = 8

This is a system of equations. You can solve it using elimination. Start by multiplying the top equation by -2.
(x * -2) + (y * -2) = (3 * -2)
-2x - 2y = -6

Now add that and the bottom equation. This will cancel out x.

     -2x - 2y = -6
+    2x + 4y = 8
-----------------------
             2y = 2

Solve for y.
2y = 2
y = 2/2
y = 1

Now plug 1 in for y in the first equation.

x + y = 3
x + 1 = 3

Solve for x.

x + 1 = 3
x = 3 - 1
x = 2

So x = 2 and y = 1.
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