The strength of the force of gravity depends ona. the masses of the objects and their speeds.
b. the masses of the objects and the distance between them.
c. the weight of the objects and their speeds.
d. the masses of the objects and their weights.
Answers
The correct answer to the question is : B) The masses of the objects and the distance between them.
EXPLANATION :
Before going to answer this question, first we have to understand Newton's law of gravitation.
As per Newton's law of gravitation, everybody in the universe attracts every other body with a force called gravitational force or force of gravity which is directly proportional to the product of masses of the two bodies, and inversely proportional to the square of separation distance between them.
Let us consider two bodies of masses M and M' which are separated by a distance R.
The gravitational force acting between them is calculated as -
Gravitational force
Here, G is known as universal gravitational force constant.
From above, we see that force of gravity depends on the masses of the objects and the distance between them.
determined by their masses and the distance between them.
Their speeds have no effect on the gravitational force, and their weight
IS the gravitational force.
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What is the correct formula for work?a. Work = force / time b. Work = force * distance c. Work = force / distance d. Work = mass * acceleration
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Which of the following best describes “the ability to do work”?a. forceb. massc. energyd. volume
Answers
The coefficient of friction between the 20 kg box and the floor is 0.2
We'll begin by calculating the acceleration of the box. This can be obtained as follow:
Initial velocity (u) = 10 m/s
Final velocity (v) = 0 m/s
Distance (s) = 25 m
Acceleration (a) =?
v² = u² + 2as
0² = 10² + (2 × a × 25)
0 = 100 + 50a
Collect like terms
0 – 100 = 50a
–100 = 50a
Divide both side by 50
a = –2 m/s²
Finally, we shall determine the coefficient of friction. This can be obtained as follow:
Mass (m) = 20 Kg
Acceleration (a) = –2 m/s²
Acceleration due to gravity (g) = 10 m/s²
Frictional Force (F) = –ma = – (20 × –2) = 40 N
Normal reaction (N) = mg = 20 × 10 = 200 N
Coefficient of friction (μ) =?
μ = 0.2
Therefore, the coefficient of friction between the box and the floor is 0.2
Learn more: brainly.com/question/11902512
The coefficient of friction between the box and the floor is 0.204.
Given data:
The mass of box is, m = 20 kg.
The initial speed of box is, u = 10 m/s.
The sliding distance is, s = 25 m.
The linear force acting on the fox is providing it necessary friction. Then,
Here, a is the linear acceleration and is the coefficient of friction between the box and the floor.
Applying the third kinematic equation of motion as,
Then,
Thus, we can conclude that the coefficient of friction between the box and the floor is 0.204.
Learn more about frictional force here:
elastic potential energy
B.
gravitational potential energy
C.
kinetic energy
D.
chemical energy
Answers
Answer:
The answer is A.
Explanation:
It's correct in Аpex
Answers
Answer:
x= x0 + v0t+ 1/2at^2
Explanation:
B) The alpha particle will reverse its direction.
C) The alpha particle will be deflected in a curve path.
Eliminate
D) The alpha particle will continue to travel in a straight line.
Answers
Answer:
C. The alpha particle will be deflected in a curve path.
Then the alpha particle will be deflected by a magnetic field.
Answers
The correct answer of this question is : From high potential to low potential.
EXPLANATION :
Before going to answer this question, first we have to understand the conventional rule for current flow.
As per the conventional rule of electricity, the current direction is opposite to the direction of electronic motion.
The current flows through a conductor is due to the motion of the free electrons. When the conductor or wire is attached to any electric source, the electrons are drifted towards the positive terminal of the source. Hence, electrons are moving from negative terminal to positive terminal.
As per the conventional rule, the current direction will be from positive terminal towards negative terminal i.e from higher potential to lower potential.
Hence, the correct answer of this question is from higher potential to lower potential .
whats the magnitude in N ?
(b) Find the centripetal acceleration of the electron.
whats the magnitude in m/s2
Answers
the electron and proton, and then we need to know the electron's mass.
I'm beginning to get the creepy feeling that, in return for the generous
5 points, you also want me to go and look these up so I can use them
in calculations ... go and collect my own straw to make the bricks with,
as it were.
Ok, Rameses:
Elementary charge . . . . . 1.6 x 10⁻¹⁹ coulomb
negative on the electron
plussitive on the proton
Electron rest-mass . . . . . 9.11 x 10⁻³¹ kg
a). The force between two charges is
F = (9 x 10⁹) Q₁ Q₂ / R²
= (9 x 10⁹ m/farad) (-1.6 x 10⁻¹⁹C) (1.6 x 10⁻¹⁹C) / (5.35 x 10⁻¹¹m)²
= ( -2.304 x 10⁻²⁸) / (5.35 x 10⁻¹¹)²
= 8.05 x 10⁻⁸ Newton .
b). Centripetal acceleration =
v² / r .
A = (2.03 x 10⁶)² / (5.35 x 10⁻¹¹)
= 7.7 x 10²² m/s² .
That's an enormous acceleration ... about 7.85 x 10²¹ G's !
More than enough to cause the poor electron to lose its lunch.
It would be so easy to check this work of mine ...
First I calculated the force, then I calculated the centripetal acceleration.
I didn't use either answer to find the other one, and I didn't use " F = MA "
either.
I could just take the ' F ' that I found, and the 'A' that I found, and the
electron mass that I looked up, and mash the numbers together to see
whether F = M A .
I'm going to leave that step for you. Good luck !