To find the equation of a line tangent to the given curve, we need to find the derivative of the curve at the point of tangency and substitute the x-coordinate of the point of tangency to find the slope. The equation of the tangent line with 0 slope and y-intercept of 8 is y = 8.
To find the equation of a line tangent to a curve, we need to find the derivative of the curve at the point of tangency.
The given curve is y = 4x² + 1 (equation 1).
First, find the derivative of equation 1, which gives us dy/dx = 8x (equation 2).
Next, substitute the x-coordinate of the point of tangency into equation 2 to find the slope of the tangent line.
Since the line cuts the y-axis at (0,8), the x-coordinate of the point of tangency is 0.
Substituting x=0 into equation 2, we get the slope of the tangent line as m = 8(0) = 0.
The equation of a line in the form y = mx + c, where m is the slope and c is the y-intercept.
Since the slope of the tangent line is 0, the equation of the tangent line is y = 0x + c. And since the line cuts the y-axis at (0,8), the y-intercept is 8.
Therefore, the equation of the tangent line is y = 8.
#SPJ3
A generic point on the graph of the curve has coordinates
The derivative gives us the slope of the tangent line at a given point:
Let k be a generic x-coordinate. The tangent line to the curve at this point will pass through and have slope
So, we can write its equation using the point-slope formula: a line with slope m passing through has equation
In this case, and , so the equation becomes
We can rewrite the equation as follows:
We know that this function must give 0 when evaluated at x=0:
This equation has no real solution, so the problem looks impossible.
240 children and 382 adult swam at the public pool that day
Solution:
Let "c" be the number of childrens
Let "a" be the number of adults
Cost of 1 child ticket = $ 1.75
Cost of 1 adult ticket = $ 2.50
622 people used the public swimming pool
Therefore,
number of childrens + number of adults = 622
c + a = 622 ------ eqn 1
The receipts for admission totaled $ 1375.00
Therefore, we can frame a equation as:
number of childrens x Cost of 1 child ticket + number of adults x Cost of 1 adult ticket = 1375.00
1.75c + 2.50a = 1375 ----- eqn 2
Let us solve eqn 1 and eqn 2
From eqn 1,
c = 622 - a -------- eqn 3
Substitute eqn 3 in eqn 2
1.75(622 - a) + 2.50a = 1375
1088.5 - 1.75a + 2.50a = 1375
0.75a = 1375 - 1088.5
0.75a = 286.5
a = 382
Substitute a = 382 in eqn 3
c = 622 - 382
c = 240
Thus 240 children and 382 adult swam at the public pool that day
the are is 24 squared
i hope this helps
Answer:
Ecuaciones algebraicas. De primer grado o lineales. De segundo grado o cuadráticas...
Ecuaciones trascendentes, cuando involucran funciones no polinómicas, como las funciones trigonométricas, exponenciales, logarítmicas, etc.
Ecuaciones diferenciales. Ordinarias...
Ecuaciones integrales.
Ecuaciones funcionales.
Hope this helps! :)
If you want to graph something on a coordinate plane online, I suggest you use Desmos. It is a free online graphing calculator.
Glad I could help!